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3 years ago

Can someone help? (On any of them)

Mathematics

1 answer:

Jet001 [13]3 years ago

8 0

Hope it helps
6) (b+4)(b+4)
8) (y-3)(y+2)
10) (y-3)(y-5)
12) (b+4)(b+5)
14) (a-3)(a-12)

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Pls help will give brainliest answer and 5star

Ipatiy [6.2K]

1. Which polygon or polygons are regular?

A regular polygon is a polygon that is equiangular (all angles are equal in measure) and equilateral (all sides have the same length).

Therefore your answer is:

A. equilateral triangle

C. square

2. Which polygon is always irregular?

traingle - NOT (equilateral triangle)

trapezoid - YES

square - NOT

hexagon - NOT (regular hexagon)

6 0

3 years ago

Find the area of the figure. (Sides meet at right angles.)

daser333 [38]

Answer:

48m squared

Step-by-step explanation:

- cut the problem in half horizontally

you get two squares one square is 4 by 4 and the other 8 by 4

4 times 4=16 8 times 4=32 32+16=48

6 0

2 years ago

Which equation represents a circle that contains the point (-5, 3) and has a center at (-2, 1)? Distance formula: vaa -02 (x - 1

natali 33 [55]

Given:

The center of the circle = (-2,1).

Circle passes through the point (-5,3).

To find:

The equation of the circle.

Solution:

Radius is the distance between the center of the circle and any point on the circle. So, radius of the circle is the distance between the points (-2,1) and (-5,3).

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$r=\sqrt{(-5-(-2))^2+(3-1)^2}$

$r=\sqrt{(-5+2)^2+(2)^2}$

$r=\sqrt{(-3)^2+(2)^2}$

On further simplification, we get

$r=\sqrt{9+4}$

$r=\sqrt{13}$

The standard form of a circle is:

$(x-h)^2+(y-k)^2=r^2$

Where, (h,k) is the center of the circle and r is the radius of the circle.

Substitute h=-2, k=1 and $r=\sqrt{13}$ .

$(x-(-2))^2+(y-1)^2=(\sqrt{13})^2$

$(x+2)^2+(y-1)^2=13$

Therefore, the equation of the circle is $(x+2)^2+(y-1)^2=13$ .

8 0

3 years ago

Line l1 passes through (-2, 5), and (-1, -10)

zalisa [80]

The equations of the lines l1 with points (-2, 5), and (-1, -10) and the line l2 with points (5, 15), and (3, 8), gives the coordinate of the intersection between the lines as the point; (-45/37, -250/37)

<h3>Which method can be used to describe the lines to find the intersection point?</h3>

The slope, m1, of line 1 l1 is found as follows;

m1 = (5 - (-10))/(-2- (-1)) = -15

The equation of line l1 in point and slope form is therefore;

y1 - 5 = -15•(x - (-2))

Which gives;

y1 = -15•(x - (-2)) + 5 = -15•x - 25

y1 = -15•x - 25

The slope, m2, of line 2 l2 is found as follows;

m2 = (15 - 8)/(5 - 3) = 3.5

Equation of line l2 is therefore;

y2 - 15 = 3.5•(x - 5)

Which gives;

y2 = 3.5•(x - 5) + 15 = 3.5•x - 2.5

y2 = 3.5•x - 2.5

At the intersection point, we have;

y1 = y2

Therefore;

-15•x - 25 = 3.5•x - 2.5

18.5•x = -22.5

x = -22.5/18.5 = -45/37

y2 = 3.5•x - 2.5

At the intersection point, we have;

y = y2 = 3.5×(-22.5/18.5) - 2.5 = -250/37

y = -250/37

The coordinates of the intersection between the lines is therefore;

(-45/37, -250/37)

Learn more about the equation of a straight line here:

brainly.com/question/13763238

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3 0

1 year ago

Write 863.141 in expanded form (THESE ARE DECIMALS)

harina [27]

800 +60 +3 + 0.1+ 0.04+ 0.001

7 0

3 years ago