A set of equations is given below:

1 answer:

4 0

The answer is: [A]: "No solution" .
_______________________________________________
Note: Given:
_______________________________________________
y = 4x + 8 ;
y = 4x + 2 ;
_______________________________________________

Since: "y = y" ;

4x + 8 = 4x + 2 ; which is not true;
______________________________
4x + 8 ≠ 4x + 2 ; since, "8 ≠ 2" ;

Note: Suppose: "4x + 8 = 4x + 2" ;

→ Subtract "4x" from each side of the equation:

4x + 8 − 4x = 4x + 2 − 4x ;

to get:
_________________
" 8 = 2 " ; not true ; since "8 ≠ 2" ;
______________________________
Also, suppose:
_______________________________
4x + 8 = 4x + 2 ;

→ Subtract "2" from BOTH SIDES of the equation;

4x + 8 − 2 = 4x + 2 − 2 ;

to get:

4x + 6 = 4x

(Note: "4x + 0 = 4x" ; but "4x + 6 ≠ 4x") l

But even if we have:

4x + 6 = 4x ;

→ Subtract "4x" from EACH side of the equation:

4x + 6 − 4x = 4x − 4x ;

to get:

6 = 0 ; which is not true; "6 ≠ 0" .
____________________________________
The correct answer is: [A]: "No solution" .
______________________________________

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Lera25 [3.4K]

Answer:

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Step-by-step explanation:

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3 years ago

A container contains water at temperature 80 degree celcius. After every 10 minutes, the change in temperature is - 4 degree cel

lilavasa [31]

For this case, the first thing we must do is define variables.
We have then:
x: number of minutes
y: final temperature
We write then the equation that models the problem:
$y = (-4/10) x + 80
$
For y = 20 we have:
$20 = (-4/10) x + 80
$
Clearing x:
$(4/10) x = 80 - 20

x = (10/4) * 60

x = 150$
Answer:
The temperature of the water will be 20 degree celcius after 150 minutes

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3 years ago

State the domain and range of both the function and the inverse function. f(x) = 8 x + 8 f -1(x) = Domain of f(x): Range of f(x)

Katena32 [7]

Answer:

$f^{-1}(x) = \frac{x+8}{8}$

Domain of f(x): All real values.

Range of f(x): All real values.

Domain of f -1(x): All real values.

Range of f -1(x): All real values

Step-by-step explanation:

We are given the following function:

$f(x) = 8x + 8$

Since it is a line, we have that both the domain is the range is the real set.

Inverse function:

The domain of the inverse function is the range of the original function, and the range of the inverse function is the domain of the original function.

Finding the inverse function:

Exchange x and y in the original function, and isolate y. So

Original

$y = 8x + 8$