Answer:
Possible lowest volume = 0.19 cm
Possible highest volume = 0.21 cm
Explanation:
Given Data
uncertainty = 0.01 cm
total volume = 0.20 cm
Possible lowest volume = ?
Possible highest volume = ?
Solution:
Possible lowest volume = total volume - uncertainty
Possible lowest volume = 0.20 cm - 0.01 cm
Possible lowest volume = 0.19 cm
Possible highest volume = total volume + uncertainty
Possible highest volume = 0.20 cm - 0.01 cm
Possible highest volume = 0.21 cm
B.) Weight.
Weight is the combination of gravity on mass, thus it produces a force. (gravity is the force)
F = G(m1 m2)/(r)^2
Let m1 be the mass of Mars
Let m2 be the mass of Deimos.
Therefore, 6m2 is the mass of Phobos.
We know that G, m1, and m2 are just constants.
Phobos:
Fp = G(m1 * 6m2)/(9000000m)^2 = 7 × 10^(-14) * G m1 m2
Deimos
Fd = G(m1 * m2)/(23000000m)^2 = 2 × 10^(-15) * G m1 m2
Mars exerts a stronger gravitational force on Phobos since Fp > Fd
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mass = density x volume
Substitute your values in
mass = 2.7 x 21
Solve:
mass = 56.7g
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Hydronium ion is H3O(+)
pH is log 1 / [H3O(+)] = - log [H3O(+)]
Rainfall: pH = 5.0 = - log [H3O(+)] => [H3O(+)] = -antilog (- 5.0) = 10^-5
Water; pH = 7.0 = - log [H3O(+)] => [H3O(+)] = - antilog (-7.0) = 10^ -7
Divide hidronium conentration of rainfall by hidrodium concentration of water:
10^-5 / 10^-7 = 10^2 = 100.
Then, hidronium concentration in rainfall is 100 times hidronium concentration in water.
Answer: option a. 100 times.
