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Aleonysh [2.5K]
3 years ago
14

If a substance is covalent, then it likely will

Chemistry
2 answers:
kati45 [8]3 years ago
5 0
Not be soluble in water
AVprozaik [17]3 years ago
4 0

Answer: Option (b) is the correct answer.

Explanation:

A substance in which bond forming between the combining atoms is due to the sharing of electrons is known as a covalent bond.

For example, bond present in a Cl_{2} molecule is a covalent bond.

Some covalent bonds are non-polar in nature whereas water is a polar solvent. As it is known that like dissolves like.  

Therefore, covalent molecules will not be soluble in water as water is a polar molecule.

Thus, we can conclude that if a substance is covalent, then it likely will not be soluble in water.

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What specific name is given to a chemical bond in which atoms share electrons?
Ira Lisetskai [31]
The type of a bond in which two atoms share their electrons is called the covalent bond. A famous example of this is the bond between two hydrogen atoms.
6 0
3 years ago
Let the simulator run for 30 seconds. What happens to the size of the ice?
Shkiper50 [21]

  1. 10 is your answer hope it helps you.......... Xd
<h2>Answer : 10 </h2>
7 0
3 years ago
Which kind of investigations never include a hypothesis?
nignag [31]

Answer:

the answer is descriptive

Explanation:

descriotive never ever have hypothisis

5 0
3 years ago
Read 2 more answers
Calcium chloride, CaCl2, is commonly used as an electrolyte in sports drinks and other beverages, including bottled water. A sol
zhannawk [14.2K]

Answer:

Mole percent of CaCl_{2} in solution is 1.71%

Explanation:

Number of moles of a compound is the ratio of mass to molar mass of the compound.

Molar mass of CaCl_{2} = 110.98 g/mol

Molar mass of H_{2}O = 18.02 g/mol

Density is the ratio of mass to volume

So, mass of 60.0 mL of water = (60\times 0.997)g=60.8g

Hence, 6.50 g of CaCl_{2} = \frac{6.50}{110.98}moles of CaCl_{2} = 0.0586 moles of CaCl_{2}

60.8 g of H_{2}O= \frac{60.8}{18.02}moles of H_{2}O = 3.37 moles of H_{2}O

So, mole percent of CaCl_{2} in solution = \frac{n_{CaCl_{2}}}{n_{total}}\times 100% = \frac{0.0586}{0.0586+3.37}\times 100% = 1.71%

5 0
4 years ago
An engine cylinder contains 175 mL of gas at a pressure of 1.0 atm. As the engine runs, it compresses the cylinder, reducing the
sukhopar [10]

This problem is providing the initial volume and pressure of a gas in an engine cylinder and asks for the final pressure once the volume of the gas has decreased due to a compression. At the end, the result turns out to be 11.7 atm.

<h3>Boyle's law</h3>

In chemistry, gas laws allow us to calculate pressure, volume, temperature or moles depending on a specified change and based on the concept and equation of the ideal gas, which derives the well-known gas laws; Boyle's, Charles', Gay-Lussac's and Avogadro's.

Thus, since this problem provides initial and final volume and initial pressure for us to calculate the final pressure, we understand we need to apply the Boyle's law as a directly proportional relationship between these two:

P_1V_1=P_2V_2

Thus, we solve for the final pressure, P2, to get:

P_2=\frac{P_1V_1}{V_2}=\frac{1.0atm*175mL}{15mL}\\ \\ P_2=11.7atm

Learn more about ideal gases: brainly.com/question/8711877

8 0
3 years ago
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