The oxidation state of the elements in the compounds are:
CoH₂:
FeBr₃:
<h3>What is the oxidation states of the elements in the given compounds?</h3>
The oxidation states of the elements in each of the given compounds is determined as follows:
Cobalt dihydride, CoH₂
Co = +2
H = -1
Iron (iii) bromide, FeBr₃
Fe = +3
Br = -1
In conclusion, the oxidation state of the elements are charges they have in the compound.
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The formula of Density is known as:
Density = mass/volume
Units: g/cm^3
Hope this helps!
Answer:
252.68 K or -20.46 °C
Explanation:
According to Gay-Lussac's Law, "Pressure and Temperature at given volume are directly proportional to each other".
Mathematically,
P₁ / T₁ = P₂ / T₂ ---- (1)
Data Given:
P₁ = 30.7 kPa
T₁ = 0.00 °C = 273.15 K
P₂ = 28.4 kPa
T₂ = <u>???</u>
Solving equation for T₂,
T₂ = P₂ T₁ / P₁
Putting values,
T₂ = 28.4 kPa × 273.15 K / 30.7 kPa
T₂ = 252.68 K or -20.46 °C
