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igomit [66]
3 years ago
15

What is the pH of an HNO3 solution with a molarity of 0.023? ( hint: pH = -log[H+] )

Chemistry
1 answer:
andrew-mc [135]3 years ago
6 0
Here you go! Let me know if you have any questions

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Which of the following equations can be used to calculate pOH?
Ivenika [448]
POH = 14 - pH
pOH = -log [OH-]
6 0
2 years ago
The analysis of compound only magnesium, phosphorus and oxygen showed 36.23% MgO and 63.77 % P2O5. set up the simplest formula
Rzqust [24]

Answer:

dfgs

Explanation:

4 0
2 years ago
___MgCl2(s) +___ MiCO3(s)
Doss [256]

Answer:

MgCl2 (s) + Li2CO3 (s) ==> MgCO3 (s) + 2LiCl (aq)

Double Replacement

Explanation:

MgCl2 (s) + Li2CO3 (s) ==> MgCO3 (s) + 2LiCl (aq)

Double Replacement

Halogens are Soluble

Carbonates are Insoluble

This reaction DOES take place.

3 0
2 years ago
In an endothermic reaction the ____ have more energy than the ____?
Ksju [112]

Answer: products; reactants

Explanation: as the endothermic reactions are tye one which absorbs energy

3 0
3 years ago
If you burn 48.6 g of hydrogen and produce 434 g of water, how much oxygen reacted?
GarryVolchara [31]

Answer:

            385.69 g of O₂

Solution:

The Balance Chemical equation for said reaction is as follow;

                                       2 H₂  +  O₂    →   2 H₂O

According to Equation,

        4.032 g ( 2 mol) H₂ reacts to produce  =  36.03 g (2 mol) of H₂O

So,

        48.6 g H₂ on reaction will produce  =  X g of H₂O

Solving for X,

                     X =  (48.6 g × 36.03 g) ÷ 4.032 g

                     X  =  434.29 g of H₂O

It means that the H₂ provided is in Excess. Therefore, the yield of product (H₂O) is being controlled by O₂ (Limiting Reagent).

So, According to Equation,

                    36.03 g (2 mol) H₂O is produced by  =  31.998 g (1 mol) of O₂

So,

                434.29 g of H₂O will be produced by  =  X g of O₂

Solving for X,

                     X =  (434.29 g × 31.998 g) ÷ 36.03 g

                    X  =  385.69 g of O₂

8 0
2 years ago
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