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myrzilka [38]
3 years ago
12

A player kicks a soccer ball from ground level and sends it flying at an angle of 30 degrees at a speed of 26 m/s. How far did t

he ball travel before it hit the ground? Round the answer to the nearest meter.
Physics
2 answers:
Furkat [3]3 years ago
3 0
What are your answers?

Agata [3.3K]3 years ago
3 0

Answer:

60m (to nearest meter)

Explanation: How far the ball traveled refers to the range covered by the ball before it hits the ground. For an object projected at an angle of ∝ to the horizontal, the range, R covered is given by;

R=u^{2}sin2\alpha/2g

Where u is the initial velocity and g is acceleration due to gravity.

u=26mls\\\alpha=30^{o}\\g=9.81m/s^{2}

The value of g could be safely assumed to be 9.8m/s^{2}

Therefore;

R=26^{2}sin2(30)/9.8

R=(26*26*sin60)/9.8

R=676*0.8660/9.8

R=59.68m which is approximately 60m to nearest meter.

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A 100 kg mass is pulled along a frictionless surface by a horizontal force F such that its acceleration is 10.0 m/s2. A 20 kg ma
DIA [1.3K]

Answer

given,

mass = 100 kg

acceleration = 10 m/s²

A mass 20 kg slides over 100 kg block

acceleration = 3 m/s²

horizontal friction exerted by the 100 kg block on 20 kg

using newton's second law

F - f = 0

F = f

f = ma

f = 20 × 3

f = 60 N

now net force acting on the 100 kg block

F_net = m a

F_net = 100 x 10

F_net = 1000 N

after 20 kg block falls the acceleration of the bock

F = 1000 +60

F = 1060 N

acceleartion on the block

a = \dfrac{F}{m}

a = \dfrac{1060}{100}

a = 10.60 m/s²

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Answer:

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