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Ksju [112]
2 years ago
5

Timed! I would really appreciate some help! thank you!

Physics
1 answer:
GenaCL600 [577]2 years ago
4 0

Answer:

x = 5[km]

Explanation:

We must convert the time from minutes to hours.

t=30[min]*\frac{1h}{60min}= 0.5[h]\\

We know that speed is defined as the relationship between space and time.

v=x/t

where:

x = space [m]

t = time = 0.5 [h]

v = velocity [m/s]

Now replacing:

x = 10[\frac{km}{h} ]*0.5[h]\\x=5[km]

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Which one of the statements below is true about mechanical waves?
ratelena [41]

Answer:

D) Mechanical waves require a medium for transmission (wire, air, etc.) as opposed to electromagnetic which travel through empty space - light, radio, etc.)

3 0
3 years ago
Two swimmers A and B, of weight 190 lb and 125 lb, respectively, are at diagonally opposite corners of a floating raft when they
Harrizon [31]

Answer:

a) 0.618 ft/s

b) 3.04 ft/s

Explanation:

<u>Givens:</u>

Weight of swimmer A W_{A} = 190 Ib.

Weight of swimmer B  W_{B}= 125 Ib.

Weight of the raft W_{R} = 300 Ib.  

Swimmer A walks toward swimmer B relative to the raft with a speed

V_{A/R}= 2 ft/s

<em>a)</em><em> Conservation of linear momentum </em>

m_{A} v_{A} +m_{B} v_{B} +m_{R} v_{R} =0..........(1)\\v_{A/R}=v_{A}  -v_{R}\\\v_{A}=v_{A/R}+v_{R}.................(2)

Since swimmer B does not move  

v_{B} =v_{R}...............(3)

Substitute from (2) and (3) into (1)

m_{A} (v_{A/R} +v_{R} )+m_{B} v_{R} +m_{R} v_{R}=0\\(m_{A}+m_{B}+m_{R})v_{R} =-m_{A}v_{A/R}\\v_{R}=\frac{-m_{A}v_{A/R}}{m_{A}+m_{B}+m_{R}} \\v_{R}=0.618ft/s

b) if the raft not to move v_{R}=0

from (2)

v_{A} =v_{A/R}

substitute in (1)

m_{A} v_{A/R} +m_{B} v_{B}+m_{R} (0)=0\\v_{B}=\frac{W_{A}v_{A/R}}{W_{B}} \\v_{B}=3.04ft/s

3 0
3 years ago
an eagle has a mass of 8 kg and is flying 85 m above the ground with a speed of 20 m/s. what is the total mechanical energy of t
vivado [14]
Total Mechanical Energy = KE + PE

KE = (1/2)mv²

     = (1/2)*8*20² = 1600 J

PE = mgh      g ≈ 10 m/s²

       = 8 * 10 * 85 = 6800J

Total Mechanical = 1600 + 6800 = 8400 J.
5 0
3 years ago
Two identical vertical springs S1 and S2 have masses m1 = 400 g and m2 = 800 g attached to them. If m1 causes spring S1 to stret
OlgaM077 [116]

Answer:

potential energy = mgh

= 400÷1000 × 10× 4÷100

= 0.4 × 10 × 0.04

=4/10 ×10×4/100

= 4/10 × 4/10

=16/100

= 0.16 joules

m1 (400) stretches 4cm

m1 (100g) stretches 1cm

so, m2(800g) stretches 8 cm

potential energy of m2 = mgh

= 800/1000 ×10×8/100

= 0.8 × 0.8

=8/10 ×8/10

= 64/100

=0.64 joules

Ratio of s1 to s2

16/100 ÷ 64/100

= 1:4 ( answer)

6 0
2 years ago
5.Projectile motion is free fall with an initial horizontal velocity. True or false
skelet666 [1.2K]

Explanation:

One of the interesting things about projectile motion is that the horizontal motion is independent of the vertical motion. Recall that in freefall, an object continually experiences a downward acceleration of 9.80ms2 but has no horizontal acceleration.

6 0
3 years ago
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