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IrinaVladis [17]
3 years ago
8

What happens when an object transfers energy?

Physics
1 answer:
Tatiana [17]3 years ago
5 0
<span>Energy is transferred from one object to another when a reaction takes place. Energy comes in many forms and can be transferred from one object to another as heat, light, or motion, to name a few. For the blue ball to move to the position of the green ball, energy must be given to the blue ball. This energy would be in the form of motion, with the person lifting the blue ball to a higher level. This form of energy is called kinetic energy.</span>
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Calculate the energy per photon and the energy per mole of photons for radiation of wavelength (a) 200 nm (ultraviolet), (b) 150
VMariaS [17]

Answer: a. E =9.9*EXP(-19)J

1 mole E= 596178J

b. E= 1.32*EXP(-15)J, 1 mole E=795MegaJ

c. E= 1.98*EXP(-23)J

1 mole E = 11.9J

Explanation: The Energy of a photon E, the wavelength are related by

E= h*c/wavelength

h is the Planck's constant 6.6*EXP(-34)J.s

c is speed of light 3*EXP(8)m/s

h*c=1.98*EXP(-25)

Now let's solve

a. E = h*c/wavelength

= h*c/(200*EXP(-9)m

=9.9*EXP(-19)J

1 mole of a photon contian 6.022*EXP(23)photons by advogadro

Now to get the energy of 1 mole of the photon we have

9.9*EXP(-19)*6.023*EXP(23)

=596178J

b. E=h*c/150*EXP(-12)m

=1.32*EXP(-15)J

1 mole will have

1.32*EXP(-15)*6.022*EXP(23)J

=795*EXP(6)J

c. E= h*c/1*EXP(-2)m

=1.98*EXP(-23)J

1 mole of the photon will have

1.98*EXP(-23)J *6.022*EXP(23)

= 11.9J.

You will notice that the longer the wavelength of the photon the lesser the Energy it as.

NOTE: EXP represent 10^

8 0
4 years ago
Adam drops a ball from rest from the top floor of a building at the same time Bob throws a ball horizontally from the same locat
guapka [62]

Answer:

Both balls hit the ground at the same time

Explanation:

Adam drops the ball from rest, so the ball just "<em>falls</em>" in vertical direction, being gravity its only acceleration, for cinematic movements we use that:

y(t)=y_{0}+v_{0y}t+\frac{1}{2}gt^{2}

In this case we have that gravity is negative, and as Adam drops the ball, v_{0y}=0

Bob throws the ball horizontally, so the movement will be a <em>parabola</em>, we can divide into horizontal direction, and vertical direction.

But we only need to analize the vertical movement, in wich again the only acceleration is gravity, and compare it with Adam's ball. Again we have that gravity is negative, and as the initial throw is horizontal, v_{0y}=0

Finally, we have that

y(t)=h-\frac{1}{2}gt^{2}

where

h=y_{0}

both for Adam's vertical drop, and for Bob's vertical component of the parabolic throw.

Now, if we put y(t)=0 (the origin of the vertical coordinate), we get for both cases that

h=\frac{1}{2}gt^{2}

where we can clear the value for the time t, of the fall, wich will be the same in both cases.

Hence, both balls hit the ground at the same time.

3 0
3 years ago
Which statement will be true if you increase the frequency of a periodic wave?
-BARSIC- [3]
"The number of waves per second will increase" is the statement among the choices given in the question that <span>will be true if you increase the frequency of a periodic wave. The correct option among all the options that are given in the question is the first option or option "A". I hope that the answer has helped you.</span>
6 0
3 years ago
Read 2 more answers
Mary has a mass of 40 kg and sprints at 1 m/s. How much kinetic energy does she have?
Sav [38]

Answer:

20 J

Explanation:

Kinetic energy is given as half of the product of mass and the square of velocity of an object:

KE = \frac{1}{2}mv^2

where m = mass = 40 kg

v = velocity = 1 m/s

Hence, Mary's kinetic energy is:

KE = \frac{1}{2} * 40 * 1^2

KE = 20 * 1 = 20 J

She has a kinetic energy of 20 J.

8 0
3 years ago
A disk initially rotated counterclockwise at 1.0 rad/s, but has a counterclockwise angular acceleration of 0.50 rad/s^2 for 2 se
Mumz [18]

Answer:

Initial angular position of the disc is 3 radian

Explanation:

As we know that the angular acceleration of the disc is given as

\alpha = 0.50 rad/s^2

initial angular speed is given as

\omega = 1 rad/s

now we know that angular displacement of the disc is given as

\theta = \omega t + \frac{1}{2}\alpha t^2

\theta = 1(2) + \frac{1}{2}(0.5)(2^2)

\theta = 3 rad

now we have

\theta_f - \theta_i = 3 rad

6 rad - \theta_i = 3

\theta_i = 3 ard

8 0
3 years ago
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