The most exact answer is 78.4J also in this kind of options we can say answer "d"
Answer:
a) t = 20 [s]
b) Can't land
Explanation:
To solve this problem we must use kinematics equations, it is of great importance to note that when the plane lands it slows down until it reaches rest, ie the final speed will be zero.
a)

where:
Vf = final velocity = 0
Vi = initial velocity = 100 [m/s]
a = desacceleration = 5 [m/s^2]
t = time [s]
Note: the negative sign of the equation means that the aircraft slows down as it stops.
0 = 100 - 5*t
5*t = 100
t = 20 [s]
b)
Now we can find the distance using the following kinematics equation.

x - xo = distance [m]
x -xo = (0*20) + (0.5*5*20^2)
x - xo = 1000 [m]
1000 [m] = 1 [km]
And the runaway is 0.8 [km], therefore the jetplane needs 1 [km] to land. So the jetpalne can't land
Technically, we don't have the information needed to calculate the current,
because you haven't mentioned the units of the 3.5 .
Since the 3.5 is a resistance, we strongly suspect ... and we'll therefore
assume ... that the 3.5 has the units of ohms. Then . . .
Current = (voltage) / (resistance) = (1.5/3.5) = <em>3/7 of an Ampere</em>.
(429 mA, rounded)
Answer:
C. Copper
Explanation:
F = Force on string
= Intial length of string
A = Area of string
E = Young's modulus of material
Change in length is given by

It can be seen that the change in length is inversely proportional to the Young's modulus of the material.
Here




So, copper will stretch the least.
Answer:
Elements in group IIA have 2 electrons in their outermost shell so they can donate these electrons of group VII A which have seven electrons in their outermost shell. So it is necessary 2 elements of group VII A, each atoms accepts one electron.
Explanation: