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Ksivusya [100]
3 years ago
10

A platinum ball weighing 100 g is removed from a furnace and dropped into 400 g of water at 0 degree C. If the equilibrium tempe

rature is 10 degrees C, and the specific heat of platinum is 0.04 cal/g degree C, what must have been the temperature of the furnace? Neglect the effect of the mass of the calorimeter.
Physics
1 answer:
kakasveta [241]3 years ago
3 0

Answer:

T = 1010 degree Celsius

Explanation:

mass of ball (Mb) = 100 g

mass of water (Mw) = 400 g

temp of water = 0 degree

specific heat of platinum (C) = 0.04 cal/g degree celsius

we can calculate the temperature of the furnace from the equation before

Mb x C x (temp of furnace (T) - equilibrium temp) = Mw x (equilibrium temp - temp of furnace)

100 x 0.04 x ( T - 10) = 400 x (10 - 0)

4 (T - 10) = 4000

T - 10 = 1000

T = 1010 degree Celsius

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The magnetic field at the center of a 1.0-cm-diameter loop is 2.5 mT.
olga nikolaevna [1]

Answer:

(a) The current in the wire is 19.89 A

(b) The distance from the wire is 0.159 cm

Explanation:

Given;

magnetic field, B = 2.5 mT

diameter of the wire, d = 1 cm

radius of the wire, r = 0.5 cm = 0.005 m

(a) The current in the wire is calculated as;

I = \frac{2Br}{\mu_0} \\\\I = \frac{2\times 2.5 \times 10^{-3} \times 0.005 }{4\pi \times 10^{-7} } \\\\I = 19.89 \ A

(b) The distance from the wire where the magnetic field is 2.5 mT is calculated as;

B = \frac{\mu_0 I}{2\pi d} \\\\where;\\\\d \ is \ the \ distance \ from \ the \  wire\\\\d = \frac{\mu_0 I}{2\pi B} = \frac{4 \pi \times 10^{-7} \times 19.89}{2\pi \times 2.5 \times 10^{-3}}  = 0.00159 \ m = 0.159 \ cm

6 0
3 years ago
With your hand parallel to the floor and your palm upright, you raise a 3-kg book upward with an acceleration of 2 m/s2. what is
kirza4 [7]

35N i don´t know why

3 0
3 years ago
Read 2 more answers
A 0.3423 g sample of pentane, C5H12, was burned in a bomb (constant-volume) calorimeter. The temperature of the calorimeter and
Yakvenalex [24]

Answer:

16.82 kJ/g

Explanation:

The Heat energy generated by the pentance combusion caused the temperature increasing of the caloriemeter and the water inside it.

Heat energy of a substace can be calculated using

Q = mcθ

C= mc

where Q = Heat energy

          m =mass

          c = specific heat capacity

          C = heat capacity

          θ =temperature difference

(Temperature difference = final temperature - initial temperature.)

heat absorbed by water = mcθ

                                         = 1  * 4.184 * (22.82-20.22)

                                         = 10.88 J --------------(1)

heat absorbed by calorimeter = Cθ

                                                  = 2210 *(22.82-20.22)

                                                  = 5746 J ---------------(2)

Combustion energy = heat absorbed by water + heat absorbed by                                                  calorimeter

Combustion energy =  10.88+ 5746 = 5756.88 J

                                 = 5.757 kJ

heat of combustion of pentane = Combustion energy / mass

                                                    = 5.757 / 0.3423

                                                    = 16.82 kJ/g

8 0
3 years ago
Qualitative studies draw conclusions.<br> True<br> False
Marina86 [1]

Answer:

Hey there!

This is false. A qualitative study is about how a thing looks, not based on any mathematical or scientific data. Quantitative studies, on the other hand, draw conclusions.

Let me know if this helps :)

3 0
3 years ago
A soccer ball is kicked at an angle of 30° to the horizontal with an initial velocity of 16 m/s. How high does the soccer ball g
Ugo [173]
Vertical component of velocity = 16sin(30°) = 8m/s

at the highest point of flight, the velocity of the ball is 0 (that moment when it stops before starting to fall) so:
v^2=u^2+2as<u />
0^2=8^2+(2\times-9.81\times s)
s= \frac{0^2-8^2}{2\times-9.81}<u />
s=3.26m

So rounding up gives option B. (3.3m)

6 0
3 years ago
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