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Anna [14]
3 years ago
7

___ is produced when grains of quartz in sandstone are welded together when the rock is subjected to high temperatures.

Physics
1 answer:
Galina-37 [17]3 years ago
3 0
Quartzite is produced when grains of quartz in sandstone are welded together when the rock is subjected to high temperatures.  Quartzite<span> or Quarzit is a hard, non-foliated metamorphic rock which was originally pure quartz sandstone. </span><span>It is formed when a quartz-rich sandstone is altered by the heat, pressure, </span>
You might be interested in
The vertical component illustrates ____ motion and the horizontal velocity component ___.
Bond [772]
Fkjsdgvfnhsdhfvaskufhgvagdhfh

4 0
3 years ago
A horizontal beam of electrons initially moving at 4.0×10^7 m/s is deflected vertically by the vertical electric field between o
givi [52]

Answer:

1.77\times 10^{-7}\ C/m^2

0.000439077936334 m

Explanation:

q = Charge of electron = 1.6\times 10^{-19}\ C

E = Electric field = 2\times 10^{4}\ N/C

\epsilon_0 = Permittivity of free space = 8.85\times 10^{-12}\ F/m

d = Distance between plates = 2 cm (assumed)

m = Mass of electron = 9.11\times 10^{-31}\ kg

The beam consists of electrons which means it has negative charge this means the upper plates will be positive and the lower plate will be negative.

The direction is upper to lower lower plate.

\epsilon_0 = Permittivity of free space = 8.85\times 10^{-12}\ F/m

Electric flux is given by

\phi=\epsilon_0E\\\Rightarrow \phi=8.85\times 10^{-12}\times 2\times 10^{4}\\\Rightarrow \phi=1.77\times 10^{-7}\ C/m^2

The charge per unit area on the plates is 1.77\times 10^{-7}\ C/m^2

Deflection is given by

s=\dfrac{1}{2}\dfrac{qE}{m}(\dfrac{d}{v})^2\\\Rightarrow s=\dfrac{1}{2}\dfrac{1.6\times 10^{-19}\times 2\times 10^4}{9.11\times 10^{-31}}(\dfrac{0.02}{4\times 10^7})^2\\\Rightarrow s=0.000439077936334\ m

The deflection is 0.000439077936334 m

7 0
3 years ago
Is a process that modifies light waves so they vibrate in a single plane
madam [21]

The process you're fishing for is "polarization", but that's a

misleading description.

Polarization doesn't do anything to change the light waves. 

It simply filters out (absorbs, as with a polarizing filter) the

light waves that aren't vibrating in the desired plane, and

allows only those that are to pass.

The intensity of a light beam is always reduced after

polarizing it, because much (most) of the original light

has been removed.

A laser light source may be thought of as an exception,

since everything coming out of the laser is polarized.

8 0
4 years ago
Aluminum wire 1.00 mm in radius is to be used to construct a solenoid 15.0 mm in radius so that the magnitude of the magnetic fi
Leto [7]

To solve this problem we will proceed to use the equations given for the calculation of the resistance, in order to find the radius of the cable. Once the length is found we can find the number of turns of the solenoid and finally the net length of it

The resistance of the wire is

R= \frac{\rho L}{A}

\rho= Resistivity

L = Length

A = Cross-sectional Area

That can be also expressed as,

R = \frac{\rho L}{\pi r^2}

Rearranging the equation for the length of the wire we have

L= \frac{R\pi r^2}{\rho}

L= \frac{3\Omega \pi(1*10^{-3})}{2.655*10^{-8}\Omega \cdot m}

L = 354.8m

The number of turns of the solenoid is

N = \frac{L}{2\pi r} \rightarrow Denominator is equal to the circumference of the loop

N = \frac{354.8}{2\pi(15*10^{-3})}

N = 3766

Finally the Length of he solenoid is

l = N (\phi)

Where \phi is the diameter of wire

l = N (2r)

l = (3766)(2*(1*10^{-3}))

l = 7.532m

Therefore the length of the solenoid is 7.532m

7 0
4 years ago
Problem 10.32
Mashcka [7]

Answer : \alpha = -240\ rad/s^{2} south

Explanation :

Given that,

Force = 200 N

Length = 2.00 m

Mass = 5.00 kg

We know that , the  formula of the angular acceleration

\alpha = \dfrac{\tau}{I}\ rad/s^{2}

We know the moment of inertia of rod

I = \dfrac{ML^{2}}{12}

Now, the torque is

\tau = F\times r

The angular acceleration

\alpha = \dfrac{F\times r\times12}{ML^{2}}

\alpha = \dfrac{((200\ N\times-1\ m) + (-200\ N)\times(1\ m))\times12}{5\ kg\times2\ m\times2\ m}

\alpha = \dfrac{-400Nm\times12}{5kg\times4m^{2}}

\alpha = -240\ rad/s^{2}  

Negative sign represent of south direction.    

Hence, this is the required solution.


7 0
3 years ago
Read 2 more answers
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