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mash [69]
2 years ago
13

Pls help me to answer this​

Physics
1 answer:
kifflom [539]2 years ago
4 0

Answers:

  1. Geography (geo-gra-phy)
  2. Location (lo-ca-tion)
  3. Coordinates (co-or-di-nates)
  4. Landmass (land-mass)
  5. Absolute (ab-so-lute)
  6. Vicinal (vi-ci-nal)
  7. Insular (in-su-lar)
  8. Relative (re-la-tive)

Note: It's very likely the tile labeled "MAL" should be "NAL", and that "MATES" should be "NATES".

==================================

Explanations:

  1. Geography deals with not only places, but also the people and cultures in those places. That's more of a social or human geography course. Natural geography talks about land formations, volcanos, rivers, etc.
  2. I'm not sure there's much to say about this term. It's simply a position in 2D or 3D space depending on context.
  3. Coordinates are things like longitude and latitude. Think of the (x,y) points on a grid. Side note: The tile "mates" should be labeled as "nates". Your teacher made a typo. In some dialects, the "co" and "or" are pronounced together; almost sounding like "core".
  4. The term "landmass" is exactly what you'd expect it should be: a big chunk of land.
  5. When you mention if a person has absolute freedom, then we consider that person having no restrictions of movement/choice/etc. It also refers to something like a local coordinate space talks about the surrounding area, whereas an absolute coordinate space doesn't have to worry about such issues. Eg: a local coordinate could be "go 5 blocks from the store" and an absolute coordinate would be to provide a GPS location. As you can see, the local coordinate space needs the store as an anchor or else it wouldn't make much sense.
  6. To be quite honest, I had a bit of a long time to find this answer. I suppose if you are good with words then it shouldn't be too much of a struggle. But I did a reverse dictionary lookup and only focused on three syllable words until I arrived at "vicinal" which is related to "vicinity". Eg: The person was just in the vicinity. Anyways, I haven't really seen this word used too much in everyday language, so that's probably why it took a while for me. I have a feeling your teacher meant to write "NAL" instead of "MAL" as one of the tiles. This appears to be the second time s/he mixed up M's with N's (the first time being "MATES" mixed up with "NATES"; see problem 3).
  7. Insular is an adjective referring to a person or group of people cut off from the larger world. Think of a small town where it's hard to reach. Islands are of course like this, but we could have an "island" rural small town or some culture in a remote location that is on a continent somewhere. It doesn't necessarily have to be a literal island surrounded by water. Think of the word "insulate" to help remember "insular". Also, the term "insular" could refer to the deliberate attempt to keep oneself (or one group) closed off from the rest of the world. An example of this is the Amish culture being insular to the American culture surrounding them.
  8. If object A is larger than object B, then we say A is relatively large  compared to B. This is one example usage of the word "relative".
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Two high-current transmission lines carry currents of 29.0 A and 78.0 A in the same direction and are suspended parallel to each
jarptica [38.1K]

Answer with Explanation:

We are given that

I_1=29 A

I_2=78 A

d=38 cm=\frac{38}{100}=0.38 m

1 m=100 cm

a.Length of segment,l=20 m

Magnetic force ,F=\frac{2\mu_0I_1I_2 l}{4\pi d}

\frac{\mu_0}{4\pi}=10^{-7}

Substitute the values

F=\frac{10^{-7}\times 29\times 78\times 20}{0.38}=0.0119 N

Hence, the magnetic force exert by each segment on the other=0.0119 N

b.We know that when current carrying in the wires are in same direction then the force will attract to each other.

Hence, the force will be attractive.

4 0
2 years ago
Read 2 more answers
Scenario
Anvisha [2.4K]

Answer:

1) t = 23.26 s,  x = 8527 m, 2)   t = 97.145 s,  v₀ = 6.4 m / s

Explanation:

1) First Scenario.

After reading your extensive problem, we are going to solve it, for this exercise we must use the parabolic motion relationships. Let's carry out an analysis of the situation, for deliveries the planes fly horizontally and we assume that the wind speed is zero or very small.

Before starting, let's reduce the magnitudes to the SI system

         v₀ = 250 miles/h (5280 ft / 1 mile) (1h / 3600s) = 366.67 ft/s

         y = 2650 m

Let's start by looking for the time it takes for the load to reach the ground.

         y = y₀ + v_{oy} t - ½ g t²

in this case when it reaches the ground its height is zero and as the plane flies horizontally the vertical speed is zero

         0 = y₀ + 0 - ½ g t2

          t = \sqrt{ \frac{2y_o}{g} }

          t = √(2 2650/9.8)

          t = 23.26 s

this is the horizontal scrolling time

          x = v₀ t

          x = 366.67  23.26

          x = 8527 m

the speed at the point of arrival is

         v_y = v_{oy} - g t = 0 - gt

         v_y = - 9.8 23.26

         v_y = -227.95 m / s

Module and angle form

        v = \sqrt{v_x^2 + v_y^2}

         v = √(366.67² + 227.95²)

        v = 431.75 m / s

         θ = tan⁻¹ (v_y / vₓ)

         θ = tan⁻¹ (227.95 / 366.67)

         θ = - 31.97º

measured clockwise from x axis

We see that there must be a mechanism to reduce this speed and the merchandise is not damaged.

2) second scenario. A catapult located at the position x₀ = -400m y₀ = -50m with a launch angle of θ = 50º

we look for the components of speed

           cos θ = v₀ₓ / v₀

           sin θ = v_{oy} / v₀

            v₀ₓ = v₀ cos θ

            v_{oy} = v₀ sin θ

we look for the time for the arrival point that has coordinates x = 0, y = 0

            y = y₀ + v_{oy} t - ½ g t²

            0 = y₀ + vo sin θ t - ½ g t²

            0 = -50 + vo sin 50 t - ½ 9.8 t²

            x = x₀ + v₀ₓ t

            0 = x₀ + vo cos θ t

            0 = -400 + vo cos 50 t

podemos ver que tenemos un sistema de dos ecuación con dos incógnitas

          50 = 0,766 vo t – 4,9 t²

          400 =   0,643 vo t

resolved

          50 = 0,766 ( \frac{400}{0.643 \ t}) t – 4,9 t²

          50 = 476,52 t – 4,9 t²

          t² – 97,25 t + 10,2 = 0

we solve the quadratic equation

         t = [97.25 ± \sqrt{97.25^2 - 4 \ 10.2}] / 2

         t = 97.25 ±97.04] 2

         t₁ = 97.145 s

         t₂ = 0.1 s≈0

the correct time is t1 the other time is the time to the launch point,

         t = 97.145 s

let's find the initial velocity

         x = x₀ + v₀ cos 50 t

         0 = -400 + v₀ cos 50 97.145

         v₀ = 400 / 62.44

         v₀ = 6.4 m / s

5 0
3 years ago
An object has a mass of 30 grams and measures 3cmx2cmx1cm. What is the density of the object?
dimulka [17.4K]
The density of the object is the ratio of its mass and volume. From the given dimensions above, we determine the volume through the equation,

      V = L x W x H

Substituting,

    V = (3 cm)(2 cm)(1 cm) = 6 cm³

From the idea presented above,
    d = m/V

Substituting the known values,

   d = (30 g)/ (6 cm³) = 5 g/cm³

ANSWER: 5 g/cm³
4 0
3 years ago
REMARKS The speed found in part (a) is the same as if the woman fell vertically through a distance of 21.9 m. The result of part
sasho [114]

Answer:

Yes, if the system has friction, the final result is affected by the loss of energy.

Explanation:

The result that you are showing is the conservation of mechanical energy between two points in the upper one, the energy is only potential and the lower one is only kinetic.

In the case of some type of friction, the change in energy between the same points is equal to the work of the friction forces

    W_{fr} = ΔEm

    W_{fr} = Em_{f} -Em₀

As we can see now there is another quantity and for which the final energy is lower and therefore the final speed would be less than what you found in the case without friction.

    Em_{f} =W_{fr} + Em₀

 

Remember that the work of the rubbing force is negative, let's write the work of the rubbing force explicitly, to make it clearer

    ½ m v² = -fr d + mgh

    v = √(-fr d 2/m + 2 gh)

    v = √ (2gh - 2fr d/m)

Now it is clear that there is a decrease in the final body speed.

Consequently, if the system has friction, the final result is affected by the loss of energy.

5 0
2 years ago
A proton traveling to the right enters a region of uniform magnetic field that points into the screen. When the proton enters th
muminat

Answer:

deflected toward bottom of the screen

Explanation:

When entering the region with magnetic field, a magnetic force is exerted on the proton. This force is perpendicular to both the direction of the magnetic field and the direction of the velocity of the proton.

The direction of the force can be determined by using the right-hand rule. We have:

- Index finger: direction of the velocity of the proton --> to the right

- Middle finger: direction of the magnetic field --> into the screen

- Thumb: direction of the magnetic force --> toward bottom of the screen

So, the correct answer is

deflected toward bottom of the screen

8 0
3 years ago
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