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2 years ago

Pls help me to answer this

Physics

1 answer:

kifflom [539]2 years ago

4 0

Answers:

Geography (geo-gra-phy)
Location (lo-ca-tion)
Coordinates (co-or-di-nates)
Landmass (land-mass)
Absolute (ab-so-lute)
Vicinal (vi-ci-nal)
Insular (in-su-lar)
Relative (re-la-tive)

Note: It's very likely the tile labeled "MAL" should be "NAL", and that "MATES" should be "NATES".

==================================

Explanations:

Geography deals with not only places, but also the people and cultures in those places. That's more of a social or human geography course. Natural geography talks about land formations, volcanos, rivers, etc.
I'm not sure there's much to say about this term. It's simply a position in 2D or 3D space depending on context.
Coordinates are things like longitude and latitude. Think of the (x,y) points on a grid. Side note: The tile "mates" should be labeled as "nates". Your teacher made a typo. In some dialects, the "co" and "or" are pronounced together; almost sounding like "core".
The term "landmass" is exactly what you'd expect it should be: a big chunk of land.
When you mention if a person has absolute freedom, then we consider that person having no restrictions of movement/choice/etc. It also refers to something like a local coordinate space talks about the surrounding area, whereas an absolute coordinate space doesn't have to worry about such issues. Eg: a local coordinate could be "go 5 blocks from the store" and an absolute coordinate would be to provide a GPS location. As you can see, the local coordinate space needs the store as an anchor or else it wouldn't make much sense.
To be quite honest, I had a bit of a long time to find this answer. I suppose if you are good with words then it shouldn't be too much of a struggle. But I did a reverse dictionary lookup and only focused on three syllable words until I arrived at "vicinal" which is related to "vicinity". Eg: The person was just in the vicinity. Anyways, I haven't really seen this word used too much in everyday language, so that's probably why it took a while for me. I have a feeling your teacher meant to write "NAL" instead of "MAL" as one of the tiles. This appears to be the second time s/he mixed up M's with N's (the first time being "MATES" mixed up with "NATES"; see problem 3).
Insular is an adjective referring to a person or group of people cut off from the larger world. Think of a small town where it's hard to reach. Islands are of course like this, but we could have an "island" rural small town or some culture in a remote location that is on a continent somewhere. It doesn't necessarily have to be a literal island surrounded by water. Think of the word "insulate" to help remember "insular". Also, the term "insular" could refer to the deliberate attempt to keep oneself (or one group) closed off from the rest of the world. An example of this is the Amish culture being insular to the American culture surrounding them.
If object A is larger than object B, then we say A is relatively large compared to B. This is one example usage of the word "relative".

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A football player kicks a ball with an initial velocity of 25 m/s at an angle of 53 degrees above the horizontal. The vertical c

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Answer:

20 m/s

Explanation:

initial velocity, u= 25m/s

u has two components. one in horizontal and in one vertical.

so,

u sin theta = vertical component.

=> u sin theta = 25× 4/5

= 20 m/s

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2 years ago

An object is placed near a concave mirror having a radius of curvature of magnitude 60 cm. How far should you place the object f

Viefleur [7K]

Answer:

u = 18 cm

Explanation:

given,

radius of curvature = 60 cm

magnification of mirror = 2.5

distance of object = ?

R = 2 f

f = R/2

f = 60/2 = 30 cm

$m = -\dfrac{v}{u}$

$2.5 = -\dfrac{v}{u}$

v = -2.5 u

now,

Using mirror formula

$\dfrac{1}{f} = \dfrac{1}{v} + \dfrac{1}{u}$

$\dfrac{1}{30} = \dfrac{1}{-2.5u} + \dfrac{1}{u}$

$\dfrac{1}{30} = \dfrac{0.6}{u}$

u = 0.6 x 30

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distance of object be equal to u = 18 cm

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3 years ago

A photoelectric effect experiment finds a stopping potential of 1.93 V when light of wavelength 200 nm is used to illuminate the

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a) Zinc (work function: 4.3 eV)

The equation for the photoelectric effect is:

$E=\phi + K$ (1)

where

$E=\frac{hc}{\lambda}$ is the energy of the incident photon, with

h = Planck constant

c = speed of light

$\lambda$ = wavelength

$\phi$ = work function of the metal

K = maximum kinetic energy of the photoelectrons emitted

The stopping potential (V) is the potential needed to stop the photoelectrons with maximum kinetic energy: so, the corresponding electric potential energy must be equal to the maximum kinetic energy,

$eV=K$

So we can rewrite (1) as

$E=\phi + eV$

where we have:

$\lambda=200 nm = 2\cdot 10^{-7} m$

V = 1.93 V

e is the electron charge

First of all, let's find the energy of the incident photon:

$E=\frac{hc}{\lambda}=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{2\cdot 10^{-7}m}=9.95\cdot 10^{-19} J$

Converting into electronvolts,

$E=\frac{9.95\cdot 10^{-19}J}{1.6\cdot 10^{-19} J/eV}=6.22 eV$

And now we can solve eq.(1) to find the work function of the metal:

$\phi = E-eV=6.22 eV-1.93 eV=4.29 eV$

so, the metal is most likely zinc, which has a work function of 4.3 eV.

b) The stopping potential is still 1.93 V

Explanation:

The intensity of the incident light is proportional to the number of photons hitting the surface of the metal. However, the energy of the photons depends only on their frequency, so it does not depend on the intensity of the light. This means that the term E in eq.(1) does not change.

Moreover, the work function of the metal is also constant, since it depends only on the properties of the material: so $\phi$ is also constant in the equation. As a result, the term (eV) must also be constant, and therefore V, the stopping potential, is constant as well.

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3 years ago

What is the capital of prince edward island

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Answer:

The capital of Prince Edward Island is Charlottetown.

Explanation:

hope this helps, and if it did, please mark brainliest :)

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3 years ago

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Answer:

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Explanation:

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2 years ago

Pls help me to answer this​

Pls help me to answer this