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3 years ago

Pls help me to answer this

Physics

1 answer:

kifflom [539]3 years ago

4 0

Answers:

Geography (geo-gra-phy)
Location (lo-ca-tion)
Coordinates (co-or-di-nates)
Landmass (land-mass)
Absolute (ab-so-lute)
Vicinal (vi-ci-nal)
Insular (in-su-lar)
Relative (re-la-tive)

Note: It's very likely the tile labeled "MAL" should be "NAL", and that "MATES" should be "NATES".

==================================

Explanations:

Geography deals with not only places, but also the people and cultures in those places. That's more of a social or human geography course. Natural geography talks about land formations, volcanos, rivers, etc.
I'm not sure there's much to say about this term. It's simply a position in 2D or 3D space depending on context.
Coordinates are things like longitude and latitude. Think of the (x,y) points on a grid. Side note: The tile "mates" should be labeled as "nates". Your teacher made a typo. In some dialects, the "co" and "or" are pronounced together; almost sounding like "core".
The term "landmass" is exactly what you'd expect it should be: a big chunk of land.
When you mention if a person has absolute freedom, then we consider that person having no restrictions of movement/choice/etc. It also refers to something like a local coordinate space talks about the surrounding area, whereas an absolute coordinate space doesn't have to worry about such issues. Eg: a local coordinate could be "go 5 blocks from the store" and an absolute coordinate would be to provide a GPS location. As you can see, the local coordinate space needs the store as an anchor or else it wouldn't make much sense.
To be quite honest, I had a bit of a long time to find this answer. I suppose if you are good with words then it shouldn't be too much of a struggle. But I did a reverse dictionary lookup and only focused on three syllable words until I arrived at "vicinal" which is related to "vicinity". Eg: The person was just in the vicinity. Anyways, I haven't really seen this word used too much in everyday language, so that's probably why it took a while for me. I have a feeling your teacher meant to write "NAL" instead of "MAL" as one of the tiles. This appears to be the second time s/he mixed up M's with N's (the first time being "MATES" mixed up with "NATES"; see problem 3).
Insular is an adjective referring to a person or group of people cut off from the larger world. Think of a small town where it's hard to reach. Islands are of course like this, but we could have an "island" rural small town or some culture in a remote location that is on a continent somewhere. It doesn't necessarily have to be a literal island surrounded by water. Think of the word "insulate" to help remember "insular". Also, the term "insular" could refer to the deliberate attempt to keep oneself (or one group) closed off from the rest of the world. An example of this is the Amish culture being insular to the American culture surrounding them.
If object A is larger than object B, then we say A is relatively large compared to B. This is one example usage of the word "relative".

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A rock is thrown vertically upward with a speed of 18.0 m/s from the roof of a building that is 50.0 m above the ground. Assume

Andreyy89

Answer:

(a) 5.7 s

(b) 39 m/s

Explanation:

(a) u = 18 m/s

At the maximum height, the final velocity of ball is zero. lte teh time taken by the ball to go from 50 m height to maximum height is t.

use first equation of motion.

v = u + g t

0 = 18 - 10 x t

t = 1.8 s

Let the maximum height attained by the ball when it thrown from 50 m height is h'.

Use third equation of motion

v^2 = u^2 + 2 g h'

0 = 18^2 - 2 x 10 x h'

h' = 16.2 m

Total height from the ground H = h + h' = 50 + 16.2 = 76.2 m

Let t' be the time taken by the ball to hit the ground as it falls from maximum height.

use third equation of motion

H = ut + 1/2 x g t'^2

76.2 = 0 + 1/2 x 10 x t'^2

t' = 3.9 s

Total time taken by the ball to hit the ground = T = t + t' = 1.8 + 3.9 = 5.7 s

(b) Let v be the velocity with which the ball strikes the ground.

v^2 = u^2 + 2 g H

v^2 = 0 + 2 x 10 x 76.2

v = 39 m/s

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4 years ago

Tom rides his motorcycle at a speed of 15 meters/second for an hour.

Dahasolnce [82]

Answer:

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3 years ago

Describe speed of light

dmitriy555 [2]

Answer:

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Explanation:

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3 years ago

Read 2 more answers

A 25.0-gram bullet enters a 2.25-kg watermelon with a speed of 220 m/s and exits the opposite side with a speed of 110 m/s. If t

umka21 [38]

Answer:

3.67 m/s

Explanation:

From the law of conservation of momentum,

Total momentum before collision = Total momentum after collision.

mu+m'u' = mv+m'v'............................... Equation 1

Where m = mass of the bullet, m' = mass of the watermelon, u = initial velocity of the bullet, u' = initial velocity of the watermelon, v = final velocity of the bullet, v' = final velocity of the watermelon.

make v' the subject of the equation,

v' = (mu+m'u'-mv)/m'....................... Equation 2

Given: m = 25 g = 0.025 kg, u = 220 m/s, m' = 2.25 kg, u' = 0 m/s ( at rest), v = 110 m/s.

Substitute into equation 2

v' =[ (0.025×220) +(2.25×0)+(0.025×110)]/2.25

v' = 3.67 m/s.

Hence the velocity of the watermelon = 3.67 m/s

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4 years ago

A wire 50.0 m long and 2.00 mm in diameter is connected to a source with a potential difference of 9.11 V, and the current is fo

Alex787 [66]

Answer:

ρ = 1.6*10⁻⁸ Ω/m.

Explanation:

Applying Ohm's Law to the wire, assuming that it can be treated as a pure resistance, the resistance of the wire can be obtained as follows:

$R = \frac{V}{I} = \frac{9.11V}{36.0A} = 0.253 \Omega (1)$

At the same time, we know that there exists a relationship between the resistance, the resistivity ρ, the length L and the area A of the wire, that is given for the following expression:

$R = \rho* \frac{L}{A} (2)$

The area of the circular section of the wire, can be expressed as a function of the diameter d, as follows:

$A = \frac{\pi*d^{2} }{4} = \frac{\pi*(0.002m)^{2}}{4} = \pi*10e-6 (3)$

Replacing the left side of (2) by (1), and (3) on the right side, we can solve for the resistivity ρ as follows:

$\rho = \frac{R*A}{L} = \frac{0.253\Omega*\pi*10e-6}{50.0m} = 1.6e-8 \Omega/m$

ρ = 1.6*10⁻⁸ Ω/m

4 0

3 years ago

Pls help me to answer this​

Pls help me to answer this