<span> attraction between the relative abundance of electrons in one object and protons in the other
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Answer:
the impulse is 14 kg-m/s and the net force applied is 14000 N
Explanation:
Given that,
The mass of a baseball, m = 0.14 kg
Initial velocity of the baseball, u = -40 m/s
Final velocity, v = 60 m/s
Time, t = 0.001 s
We need to find the impulse and average net force applied to the ball by the bat.
Impulse = change in momentum
i.e.
J = m(v-u)
J = 0.14 × (60-(-40))
J = 14 kg-m/s
Now,
J = Ft
F is average force applied to the ball
So,
So, the impulse is 14 kg-m/s and the net force applied is 14000 N.
Answer: Yes both gases would have the same entropy.
Explanation:
The formula for the change in the entropy is as follows,
Here, \Delta S is the change in the entropy, Q is the heat transfer and T is the temperature.
If the temperature of the system increases then there will be increase in the entropy as the randomness of the system increases.
In the given problem, if the both gases were initially at the same absolute temperature. Then there will be same entropy change in both gases.
Therefore, yes both gases would have the same entropy.