Answer:
the wave represents the second harmonic.
Explanation:
Given;
length of the cord, L = 64 cm
The first harmonic of a cord fixed at both ends is given as;

The wavelength of a standing wave with two antinodes is calculated as follows;
L = N---> A -----> N + N ----> A -----> N
Where;
N is node
A is antinode
L = N---> A -----> N + N ----> A -----> N = λ/2 + λ/2
L = λ
The harmonic is calculated as;

Therefore, the wave represents the second harmonic.
L = λ
<h2>
Answer:</h2>
4.2 C
<h2>
Explanation:</h2>
The charge (Q) moving is the product of the current(I) flowing through the torso of the person and the time taken (t) for the flow.
i.e
Q = I x t
Where;
I = current = 14.0A
t = time taken = 0.0300s
Substituting the values of I and t into the equation above gives
Q = 14.0 x 0.0300
Q = 4.2 C
Therefore quantity of charge moving is 4.2 C
Answer:
A: 4
B: 7
C. 3
Source:
Trust me bro
(Don’t act put this I jus need to answer questions sorry)<\3
Since U=0,
h=1/2gt^2 (h= ut+1/2gt^2, U=0)
h=1/2*10*4*4
h=80m