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Mamont248 [21]
3 years ago
5

The terminal velocity of a person falling in air depends upon the weight and the area of the person facing the fluid.

Physics
1 answer:
kolbaska11 [484]3 years ago
5 0

Answer:

The terminal velocity of the diver is 115 m/s = 414 km/hr

Explanation:

At terminal velocity,

Fnet = mg - Fd = 0

Drag force, Fd = cρAv²/2

mg = cρAv²/2

Terminal Velocity of a body falling through a fluid as in a diver falling through air is given by

v = √(2mg/ρcA)

where m = mass of body falling through fluid = 80 kg

g = acceleration due to gravity = 9.8 m/s²

ρ = density fluid, density of air, as obtained from literature = 1.21 kg/m³

c = coefficient of drag friction of diver falling through air, as obtained from literature = 0.7

A = the area of the diver facing the fluid = 0.14 m²

v = √(2mg/ρcA) = √((2 × 80 × 9.8)/(1.21 × 0.7 × 0.14)) = 115 m/s = 115 × (3600/1000) km/hr = 414 km/hr

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Consider the electronic elements that are cooled by forced convection in Problem 6.31. The cooling system is designed and tested
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Answer:

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Explanation:

from the energy balance equation we have to:

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k=0.0269 W/(m*K)

Pr=0.703

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the surface temperature at Mexico City is equal to:

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3 years ago
A basketball has a coefficient of restitution of 0.821 in collisions with the wood floor of a basketball court. The ball is drop
Tanya [424]

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Explanation:

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Where

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At fourth bounce ,   we have that

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Putting the given values and solving , we have,

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0.2064 x 2.07 = 0.427 = 0.43

At  fourth bounce,  h₄ height = 0.43m

7 0
3 years ago
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lozanna [386]
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1 year ago
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