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2 years ago

11

a low tide and a high tide occur in the oceans two times each day. which factor has the greatest effect on the size of the tides

?

1 answer:

Dmitrij [34]2 years ago

7 0

Answer:

The gravitational pull from the Moon has the greatest effect on the size of the tides.

Hope this helps, :)

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A flat sheet of ice has a thickness of 2.20 cm. It is on top of a flat sheet of crystalline quartz that has a thickness of 1.50

kolezko [41]

Answer:

$Distance_{vaccum}=5.19cm$

Explanation:

The speed of light in these mediums shall be lower than that in vacuum thus the total time light needs to cross both the media are calculated as under

Total time = Time taken through ice + Time taken through quartz

Time taken through ice = Thickness of ice / (speed of light in ice)

$T_{ice}=\frac{2.20\times 10^{-2} \times \mu _{ice}}{V_{vaccum}}$

$T_{quartz}=\frac{1.50\times 10^{-2} \times \mu _{quartz}}{V_{vaccum}}$

Thus in the same time the it would had covered a distance of

$Distance_{vaccum}=Totaltime\times V_{vaccum}\\\\Distance_{vaccum}=10^{-2}[2.20\mu _{ice+1.50\mu _{quartz}}]$

we have

$\mu _{ice}=1.309\\\\\mu _{quartz}=1.542$

Applying values we have

$Distance_{vaccum}=10^{-2}[2.20\times 1.309+1.50\times 1.542]$

$Distance_{vaccum}=5.19cm$

6 0

3 years ago

Any unit of acceleration MUST have the form of _____.

KengaRu [80]

Any unit of acceleration must have the dimensions (form) of

(a unit of length) / (a unit of time)²

7 0

2 years ago

A merry-go-round of radius R, shown in the figure, is rotating at constant angular speed. The friction in its bearings is so sma

mel-nik [20]

The angular speed of the merry-go-round reduced more as the sandbag is

placed further from the axis than increasing the mass of the sandbag.

The rank from largest to smallest angular speed is presented as follows;

[m = 10 kg, r = 0.25·R]

${}$ ⇩

[m = 20 kg, r = 0.25·R]

${}$ ⇩

[m = 10 kg, r = 0.5·R]

${}$ ⇩

[m = 10 kg, r = 0.5·R] = [m = 40 kg, r = 0.25·R]

${}$ ⇩

[m = 10 kg, r = 1.0·R]

Reasons:

The given combination in the question as obtained from a similar question online are;

<em>1: m = 20 kg, r = 0.25·R</em>

<em>2: m = 10 kg, r = 1.0·R</em>

<em>3: m = 10 kg, r = 0.25·R</em>

<em>4: m = 15 kg, r = 0.75·R</em>

<em>5: m = 10 kg, r = 0.5·R</em>

<em>6: m = 40 kg, r = 0.25·R</em>

According to the principle of conservation of angular momentum, we have;

$I_i \cdot \omega _i = I_f \cdot \omega _f$

The moment of inertia of the merry-go-round, $I_m$ = 0.5·M·R²

Moment of inertia of the sandbag = m·r²

Therefore;

0.5·M·R²· $\omega _i$ = (0.5·M·R² + m·r²)· $\omega _f$

Given that 0.5·M·R²· $\omega _i$ is constant, as the value of m·r² increases, the value of $\omega _f$ decreases.

The values of m·r² for each combination are;

Combination 1: m = 20 kg, r = 0.25·R; m·r² = 1.25·R²

Combination 2: m = 10 kg, r = 1.0·R; m·r² = 10·R²

Combination 3: m = 10 kg, r = 0.25·R; m·r² = 0.625·R²

Combination 4: m = 15 kg, r = 0.75·R; m·r² = 8.4375·R²

Combination 5: m = 10 kg, r = 0.5·R; m·r² = 2.5·R²

Combination 6: m = 40 kg, r = 0.25·R; m·r² = 2.5·R²

Therefore, the rank from largest to smallest angular speed is as follows;

Combination 3 > Combination 1 > Combination 5 = Combination 6 >

Combination 2

Which gives;

[<u>m = 10 kg, r = 0.25·R</u>] > [<u>m = 20 kg, r = 0.25·R</u>] > [<u>m = 10 kg, r = 0.5·R</u>] > [<u>m = </u>

<u>10 kg, r = 0.5·R</u>] = [<u>m = 40 kg, r = 0.25·R</u>] > [<u>m = 10 kg, r = 1.0·R</u>].

Learn more here:

brainly.com/question/15188750

6 0

1 year ago

The total blood volume of a human is 75 ml/kg. If the volumetric flow rate is the same in adults and children, how much more blo

Tema [17]

The amount of blood that flows through the venae cavea of the adult is 3750 ml more than that of the child.

<h3>What is flow rate?:</h3>

This is the volume of fluid flowing in a vessel per unit time.

First, we need to get the volume of blood flowing through the venae cavae of the adult and the child in 1 hour, then subtract the volume of blood for the child from that of the adult.

Using,

V = F'm................ Equation 1

Where:

V = Volume of the blood
F' = Flow rate
m = mass of blood.

For the Adult,

Given:

m = 70 kg
F = 75 ml/kg

Substitute these values into equation 1

V = 70(75)
V = 5250 ml.

For the child,

Given:

m = 20 kg
F = 75 ml/kg

Substitute these values into equation 1 also

V = 75(20)
V = 1500 ml.

The amount of blood that flows more through the adult than the child is

A = 5250-1500
A = 3750 ml.

Hence, the amount of blood that flows through the venae cavea of the adult is 3750 ml more than that of the child.

Learn more about flow rate here: brainly.com/question/21630019

5 0

2 years ago

The ???? ,of an object is a vector that is directed toward<br> the center of the Earth.

Aleks04 [339]

<u>The Weight </u>is a vector whose magnitude is the product of the mass m of the object and the magnitude of the local gravitational acceleration. Its always directed toward the center of the Earth.

5 0

2 years ago