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tester [92]
3 years ago
11

a low tide and a high tide occur in the oceans two times each day. which factor has the greatest effect on the size of the tides

?
Physics
1 answer:
Dmitrij [34]3 years ago
7 0

Answer:

The gravitational pull from the Moon has the greatest effect on the size of the tides.

Hope this helps, :)

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A train travelling at 20 m/s has 2 000 000 J of kinetic energy. What is the mass of<br> the train?
Svetlanka [38]

Answer:

<h2>10,000 kg</h2>

Explanation:

The mass of the train can be found by using the formula

m =  \frac{2k}{ {v}^{2} }  \\

k is the kinetic energy

v is the velocity

From the question we have

m \frac{2(2000000)}{ {20}^{2} }  =  \frac{4000000}{400}  =  \frac{40000}{4}  \\

We have the final answer as

<h3>10,000 kg</h3>

Hope this helps you

3 0
3 years ago
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What is the Sl unit for momentum?<br> O kg• m<br> O kg<br> O kg• m<br> O kg<br> 2<br> m
Andrej [43]

Explanation:

<h2><em>The </em><em>S. </em><em>I. </em><em> </em><em>unit </em><em>of </em><em>momentum </em><em>is </em><em>Kg. </em><em>m/</em><em>s</em><em>e</em><em>c</em></h2>

<em>hope </em><em>it </em><em>helps </em><em>you </em>

8 0
3 years ago
Which of the graphs describes the motion of a person who first rode her bicycle at constant speed and then rested?
sergeinik [125]

Answer:

Its graph 1

Explanation:

She started at the origin and kept riding her bike until she stopped which causes the line to go staright because she's not moving.

5 0
2 years ago
A solenoid coil with 22 turns of wire is wound tightly around another coil with 340 turns. The inner solenoid is 25.0 cm long an
LUCKY_DIMON [66]

Answer:

a) 1.34*10^-8 W

b) 1.18*10^-5 H

c) 20mV

Explanation:

a) To find the average magnetic flux trough the inner solenoid you the following formula:

\Phi_B=BA=\mu_oNIA

mu_o: magnetic permeability of vacuum = 4pi*10^-7 T/A

N: turns of the solenoid = 340

I: current of the inner solenoid = 0.100A

A: area of the inner solenoid = pi*r^2

r: radius of the inner solenoid = 2.00cm/2=1.00cm=10^-2m

You calculate the area and then replace the values of N, I, mu_o and A to find the magnetic flux:

A=\pi(10^{-2}m)^2=3.141510^{-4}m^2\\\Phi_B=(4\pi*10^{-7}T/A)(340)(0.100A)(3.1415*10^{-4}m^2)=1.34*10^{-8}W\\

the magnetic flux is 1.34*10^{-8}W

b) the mutual inductance is given by:

M=\mu_o N_1 N_2 \frac{A_2}{l}

N1: turns of the outer solenoid = 22

N2: turns of the inner solenoid

A_2: area of the inner solenoid

l: length of the solenoids = 25.0cm=0.25m

by replacing all these values you obtain:

M=(4\pi*10^{-7}T/A)(340)(22)\frac{3.14*10^{-4}m^2}{0.25m}=1.18*10^{-5}H

the mutual inductance is 1.18*10^{-5}H

c) the emf induced can be computed by using the mutual inductance and the change in the current of the inner solenoid:

\epsilon_1=M\frac{dI_2}{dt}

by replacing you obtain:

\epsilon_1=(1.18*10^{-5}H)(1700A/s)=0.02V=20mV

the emf is 20mV

7 0
3 years ago
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mamaluj [8]
In a displacement/time graph, the slope of the line is equal to the velocity
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