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3 years ago

A 10 kg object is travelling at 2.0 m/s. After 30 seconds the object's speed becomes 3.0

Physics

2 answers:

belka [17]3 years ago

7 0

I think this might be the answer, if it is I’ll be very surprised =/

mylen [45]3 years ago

3 0

Answer:7350 joules

Explanation:

Mass(m)=10kg

Initial velocity(u)=2m/s

Final velocity(v)=3m/s

Time(t)=30s

Acceleration horizontally=a

Acceleration due to gravity(g)=9.8m/s^2

d=(u+v)/2 x t

d=(2+3)/2 x30

d=5/2 x 30

d=(5x30)/2

d=150/2

d=75

Force=mass x acceleration due to gravity

Force=10x9.8

Force=98N

Work=force x distance

Work=98 x 75

Work=7350J

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3 years ago

How many atoms are in 3MgCl2?

Bogdan [553]

Answer:

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Explanation:

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8 0

3 years ago

A 4.8 mF capacitor in series with a 500 Ω resistor is connected, by a switch, to a 12 V battery. The current through the resisto

ad-work [718]

Answer:

Current will be 81.7 mA

Which is not given in bellow option

Explanation:

We have given capacitance $C=4.8mF=4.8\times 10^{-3}F$

Resistance R = 500 ohm

Voltage V = 12 volt

We know that time constant of RC circuit of RC circuit is given by

$\tau =RC=500\times 4.8\times 10^{-3}=2.4sec$

Time is given as t = 1 sec

We know that current in RC circuit is given by

$i=\frac{v}{R}(1-e^{\frac{-t}{\tau }})$

So current $i=\frac{12}{500}(1-e^{\frac{-1}{2.4 }})=0.00817A=81.7mA$

Which is not given in the following option

3 0

3 years ago

Read 2 more answers

A piston/cylinder contains 2 kg of water at 20◦C with a volume of 0.1 m3. By mistake someone locks the piston, preventing it fro

morpeh [17]

Answer:

Final temperature = 250.11 °C

Final volume = 0,1 m3.

Process work = 0

Explanation:

The specific volume in the initial state is: v = 0.1m3/2 kg = 0.05 m3/kg.

This volume is located between the volumes as saturated liquid and saturated steam at 20 °C. For this reason the water is initially in a liquid vapor mixture. As the piston was blocked the volume remains constant and the process is isometric, also known as isocoric process, so the final temperature will be the water temperature at a saturated steam of v=0.05m3/kg, which is obtained by using steam tables for water, by linear interpolation. As follows, using table A-4 of the Cengel book 7th Edition:

v=0.05 m3/kg

v1=0.057061 m3/kg

T1=242.56°C

v2=0.049779 m3/kg

T2=250.35°C

T= $\frac{T2-T1}{v2-v1} x(v-v1)+T1=\frac{250.35°C-242.56°C}{0.049779m3/kg-0.057061m3/kg}x(0.05m3/kg-0.057061m3/kg)+242.56°C=250.11°C$

The process work is zero because there is no change in volume during heating:

W=PxΔv=Px0=0

where

W=process work

P=pressure

Δv=change of volume, is zero because the piston was blocked so the volume remains constant.

7 0

3 years ago