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marishachu [46]
3 years ago
10

How does air resistance affect the acceleration of falling objects?

Physics
1 answer:
BlackZzzverrR [31]3 years ago
7 0
Air resistance opposes the motion of falling objects. Dense air prefers to stay at low heights. More dense the air is, more air resistance it produces. Hence acceleration of falling objects decreases. Hope this helps!
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If<br> an object has a volume of 2.5 mL and a mass of 10 g, what is the density of the object?
skad [1K]
We know, density = mass /volume 
Here, m = 10 g
v = 2.5 mL = 2.5 cm³

Substitute their values, 
density = 10/2.5
<span>d = 4 g/cm³
</span>
In short, Your Answer would be <span>4 g/cm³</span>

Hope this helps!
4 0
3 years ago
Read 2 more answers
Important!
andreyandreev [35.5K]

Answer:

b

Explanation:

8 0
3 years ago
Please I need your help
frez [133]
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A step-down transformer has 2500 turns on its primary and 5.0 x 10' tums on its secondary. If the potential difference across th
Brilliant_brown [7]

Answer:

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Explanation:

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4 0
3 years ago
irius, the brightest star in the sky, is 2.6 parsecs (8.6 light-years) from Earth, giving it a parallax of 0.379 arcseconds. Ano
Norma-Jean [14]

The actual distance of Regulus from Earth is 23.81 parsecs.

Given:

Parallax of Regulus, p = 0.042 arc seconds

Calculation:

When an observer changes their position, an apparent change in the object's position takes place. This change can be calculated using the angle ( or semi-angle) made by the observer and object i.e. the angle made between the two lines of observation from the object to the observer.

Thus from the relation of parallax of a celestial body we get:

S = 1/ tan p ≈ 1 / p

where S is the actual distance between the object and the observer

            p is the parallax angle observed

Here for Regulus, we get:

S = 1 / p

  = 1 / (0.042)                                     [ 1 parsecs = 1 arcseconds ]

  = 23.81 parsecs

We know that,

1 parsecs = 3.26 light-years = 206,000 AU

Converting the actual distance into light years we get:

23.81 parsecs = 23.81 × (3.26 light yrs) = 77.658 light-years

Therefore, the actual distance of Regulus from Earth is 23.81 parsecs which is 77.658 in light years.

Learn more about astronomical units here:

<u>brainly.com/question/16471213</u>

#SPJ4

6 0
1 year ago
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