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vlada-n [284]
3 years ago
14

Twin skaters approach each other with identical speeds. Then, the skaters lock hands and spin. Calculate their final angular vel

ocity, given each had an initial speed of 2.50 m/s relative to the ice. Each has a mass of 70.0 kg, and each has a center of mass located 0.800 m from their locked hands. You may approximate
Physics
1 answer:
kherson [118]3 years ago
5 0

Answer:

\omega=3.135rad/s

Explanation:

From the question we are told that:

initial Speed V_1=2.50

Mass m=70.0kg

Center of mass d=0.0.800m\

Generally the equation for angular velocity is is mathematically given by

\omega=\frac{v}{r}\\\\\omega=\frac{2.50}{0.0800}

\omega=3.135rad/s

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Answer:

Q = 12540  J

Explanation:

It is given that,

Mass of water, m = 50 mL = 50 g

It is heated from 0 degrees Celsius to 60 degrees Celsius.

We need to find the energy required to heat the water. The formula use to find it as follows :

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2 years ago
A handful of professional skaters have taken a skateboard through an inverted loop in a full pipe. For a typical pipe with a dia
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Answer

given,

diameter of the pipe is  =  (14 ft)4.27 m

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F = mg

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v = \sqrt{gr}

r = d/2 = 14/ 2 = 7 ft

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3 years ago
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Answer

given,

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now, inserting the value of equation (1)

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