The magnification of the image is -⅓
<h3>Further explanation</h3>
<em>We will solve this problem using following formula:</em>
where:
<em>so = distance of object from lens</em>
<em>si = distance of image from lens</em>
<em>f = focal length of lens</em>
<em>M = magnification of lens</em>
<u>Given:</u>
focal length of diverging lens = -f
distance of object from lens = so = 2f
<u>Asked:</u>
magnification of the image = M = ?
<u>Solution:</u>
<em>Firstly , we will find the distance of image from lens as follows :</em>
<em>Next , we could calculate the magnification of the lens as follows :</em>
<h3>Conclusion :</h3>
The magnification of the image is -⅓
<h3>Learn more</h3>
<h3>Answer details</h3>
Grade: High School
Subject: Physics
Chapter: Light - Diverging Lens