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3 years ago

Which of the following would have the smallest gravitational attraction between the two masses?

Physics

2 answers:

ziro4ka [17]3 years ago

5 0

The 3rd one

Explanation:

Becuse it has log distance and the mass are small than others, means the attraction will be less in this case

expeople1 [14]3 years ago

3 0

Answer: Distance= 100,000 km

Mass= 15 million kg Mass= 5 million kg

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You walk to the corner store at 2 m/s for a total time of 76 seconds. What is the distance to the store?

blsea [12.9K]

Answer:

152.

Explanation:

2 x 76 = 152

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2 years ago

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According to Newton's 3rd law of motion, if you hit a baseball with a bat it will _____.

Anna [14]

Fly in a straight line unless an outside force changes its course because i tried it once in a baseball game that my mommy rekt me in.

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2 years ago

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A heat pump is to be used for heating a house in winter. The house is to be maintained at 70°F at all times. When the temperatur

Anna35 [415]

Answer:

$\dot{W_{H} } = 4244.48 Btu/h$

Explanation:

Temperature of the house, $T_{H} = 70^{0} F$

Convert to rankine, $T_{H} = 70^{0}+ 460 = 530 R$

Heat is extracted at 40°F i.e $T_{L} = 40^{0}F = 40 + 460 = 500 R$

Calculate the coefficient of performance of the heat pump, COP

$COP = \frac{T_{H} }{T_{H} - T_{L} } \\COP = \frac{530 }{530 - 500 }\\ COP = \frac{530}{30} \\COP = 17.67$

The minimum power required to run the heat pump is given by the formula:

$\dot{W_{H} } = \frac{\dot{Q_{H} }}{COP} \\$ ...............(*)

Where the heat losses from the house, $\dot{Q_{H} } = 75,000 Btu/h$

Substituting these values into * above

$\dot{W_{H} } = \frac{75000}{17.67} \\ \dot{W_{H} } = 4244.48 Btu/h$

3 0

2 years ago

A particle of mass 4.00 kg is attached to a spring with a force constant of 100 N/m. It is oscillating on a frictionless, horizo

zloy xaker [14]

Solution :

Given :

Mass attached to the spring = 4 kg

Mass dropped = 6 kg

Force constant = 100 N/m

Initial amplitude = 2 m

Therefore,

a). $v_{initial} = A w$

$= 2 \times \sqrt{\frac{100}{4}}$

= 10 m/s

Final velocity, v at equilibrium position, v = 5 m/s

Now, $\frac{1}{2}(4+4)5^2 = \frac{1}{2} kA'$

A' = amplitude = 1.4142 m

b). $T=2 \pi \sqrt{\frac{m}{k}}$

m' = 2m

Hence, $T'=\sqrt2 T$

c). $\frac{\frac{1}{2}(4+4)5^2 + \frac{1}{2}\times 4 \times 10^2}{\frac{1}{2} \times 4 \times 10^2}$

$=\frac{1}{2}$

Therefore, factor $=\frac{1}{2}$

Thus, the energy will change half times as the result of the collision.

7 0

2 years ago

What are compounds considered to be

bija089 [108]

Answer:A compound is a substance formed when two or more elements are chemically joined.

Explation:Water, salt, and sugar are examples of compounds.

I hope this helps<3

7 0

2 years ago