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zhuklara [117]
3 years ago
8

Which of the following would have the smallest gravitational attraction between the two masses?

Physics
2 answers:
ziro4ka [17]3 years ago
5 0

The 3rd one

Explanation:

Becuse it has log distance and the mass are small than others, means the attraction will be less in this case

expeople1 [14]3 years ago
3 0

Answer: Distance= 100,000 km

   Mass= 15 million kg        Mass= 5 million kg

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strojnjashka [21]

Answer:

Holi

biwali

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7 0
3 years ago
What is the density of a piece of wood with a mass of 25 kg<br> and a volume of 0.0385 m³?
Orlov [11]

Answer:

649kg/m^3

Explanation:

Let p be the density of this particular object.

Formula for density:

p =  \frac{mass \: (in \: kg)}{volume \: (in \:  {m}^{3}) }

We can substitute the givenmass and volume to find density of the object.

p =  \frac{25kg}{0.0385 {m}^{3} }  \\  = 649kg \: per \:  {m}^{3}

Therefore the density of this object is 649kg/m^3.

7 0
2 years ago
Two identical charges q placed 2.0 mapart exert forces of magnitude 4.0 N on each other What is the value of the charge q? a) q
katen-ka-za [31]

Answer:

c) 4.2*10^{-5}C

Explanation:

Coulomb's law says that the force exerted between two charges is inversely proportional to the square of distance between them, and is given by the expression:

F=\frac{kq_{1}q_{2}}{r^{2}}

where k is a proportionality constant with the value k=9*10^{9}\frac{Nm^{2}}{C^{2}}

In this case q_{1}=q_{2}=q, so we have:

F=\frac{kq^{2}}{r^{2}}

Solving the equation for q, we have:

kq^{2}=Fr^{2}

q^{2}=\frac{Fr^{2}}{k}

q=\sqrt{\frac{Fr^{2}}{k}}

Replacing the given values:

q=\sqrt{\frac{4.0N*(2.0m)^{2}}{9*10^{-9}\frac{Nm^{2}}{C^{2}}}}

q=4.2*10^{-5}C

3 0
3 years ago
True or false. there would be no like in earth without the sun
alisha [4.7K]

hello!

True

have a goed day

6 0
3 years ago
An ambulance is traveling north at 55.9 m/s, approaching a car that is also traveling north at 28.4 m/s. The ambulance driver he
wlad13 [49]

Answer:

915 Hz

Explanation:

The observed frequency from a sound source is given as

f₀ = f [(v + v₀)/(v+vₛ)]

where

f₀ = observed frequency of the sound by the observer = ?

f = actual frequency of the sound wave = 983 Hz

v = actual velocity of the sound waves = 343 m/s

vₛ = velocity of the source of the sound waves = 55.9 m/s

v₀ = velocity of the observer = 28.4 m/s

f₀ = 983 [(343+28.4)/(343+55.9)]

f₀ = 915.2 Hz = 915 Hz

6 0
3 years ago
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