Ask question

Ask question

All categories

mihalych1998 [28]

2 years ago

7

Pravat exerts a force of 30 N to lift a bag of groceries 0. 5 m. How much work did Pravat do on the bag? Note : Work = Force x D

istance 0 J 15 J 30 J 60 J.

2 answers:

Black_prince [1.1K]2 years ago

8 0

The amount of work done by Pravat if he exerts a force of 30 N to lift a bag of groceries 0.5m is 15J.

<h3>WORK DONE:</h3>

The work done by a body can be calculated by multiplying the force exerted by the distance moved. That is;

Work done = force (F) × distance (m)

According to this question, Pravat exerts a force of 30N to lift a bag of groceries 0.5 m. The work done is calculated as follows:

Work done = 30N × 0.5m

Work done = 15J

Therefore, the amount of work done by Pravat if he exerts a force of 30 N to lift a bag of groceries 0.5m is 15J.

Learn more about work done at: brainly.com/question/8119756?referrer=searchResults

ch4aika [34]2 years ago

8 0

Answer:

<h2>15 J</h2>

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 30 × 0.5 = 15

We have the final answer as

<h3>15 J</h3>

Hope this helps you

You might be interested in

What is the potential difference when the current in a circuit is 5mA and resistance is 30 Ohms

Mashcka [7]

<h2> $\bf{ \underline{Given:- }}$ </h2>

$\sf• \: The \: current \: in \: a \: circuit \: is \: 5 \: amps. \: and \: resistance \: is \: 30 \: Ohms.$

$\\$

<h2> $\bf{ \underline{To \: Find :- }}$ </h2>

$\sf{• \: The \: Potential \: Difference. }$

$\\$

$\huge\bf{ \underline{ Solution:- }}$

$\sf According \: to \: the \: question,$

$\sf• \: Current \: (I) = 5 \: Amps.$

$\sf• \: Resistance \: (R) = 30 \: Ω$

$\sf{Potential \: difference \: means \: Voltage \: ( V).}$

$\sf{We \: know \: that, }$

$\bf \red{ \bigstar{ \: V = IR }}$

$\rightarrow \sf V =5 \times 30$

$\rightarrow \sf V =150$

$\\$

$\sf \purple{Therefore, \: the \: potential \: difference \: is \: 150 \: v \: .}$

4 0

3 years ago

A 500.-kg roller coaster car starts from rest at the top of a 60.0-meter hill.

Paraphin [41]

1.47x10^5 Joules
The gravitational potential energy will be the mass of the object, multiplied by the height upon which it can drop, multiplied by the local gravitational acceleration. And since it started at the top of a 60.0 meter hill, halfway will be at 30.0 meters. So
500 kg * 30.0 m * 9.8 m/s^2 = 147000 kg*m^2/s^ = 147000 Joules.
Using scientific notation and 3 significant figures gives 1.47x10^5 Joules.

8 0

3 years ago

Hii! help asap. i’ll give brainliest thanks!

o-na [289]

I believe it’s the mass of the box but I don’t no if I’m right

Hope this helped

5 0

3 years ago

Why all traveller prefer to travel easily in the morning and night and not when the sun is hot

eduard

Answer:

Travelers prefer to travel in morning because arthat time the temperature ️ is not too hot and they can easily travel here and there without any problem. and they also prefer to travel in night because moderate temperature ....

4 0

3 years ago

A Van de Graaff generator is one of the original particle accelerators and can be used to accelerate charged particles like prot

Rzqust [24]

Answer:

595391.482946 m/s

$3.21875\times 10^{6}$

Explanation:

E = Energy = 1.85 keV

I = Current = 5.15 mA

e = Charge of electron = $1.6\times 10^{-19}\ C$

t = Time taken = 1 second

m = Mass of proton = $1.67\times 10^{-27}\ kg$

Velocity of proton is given by

$v=\sqrt{\dfrac{2E}{m}}\\\Rightarrow v=\sqrt{\dfrac{2\times 1.85\times 10^3\times 1.6\times 10^{-19}}{1.67\times 10^{-27}}}\\\Rightarrow v=595391.482946\ m/s$

The speed of the proton is 595391.482946 m/s

Current is given by

$I=\dfrac{\Delta Q}{t}\\\Rightarrow \Delta Q=It\\\Rightarrow \Delta Q=5.15\times 10^{-3}\times (1\ sec)\\\Rightarrow Q=5.15\times 10^{-3}\ C$

Number of protons is

$n=\dfrac{Q}{e}\\\Rightarrow n=\dfrac{5.15\times 10^{-3}}{1.6\times 10^{-19}}\\\Rightarrow n=3.21875\times 10^{6}\ protons$

The number of protons is $3.21875\times 10^{6}$

3 0

4 years ago