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puteri [66]
3 years ago
8

Why is an MRI is useful for diagnosing cancer but ineffective in treating it?

Chemistry
1 answer:
LekaFEV [45]3 years ago
5 0
Bc an MRI is just a scanner it's not and never will be meant for treatment 
You might be interested in
2NaHCO3-->Na2CO3+H2O+CO2
algol [13]
I’m not sure what kind of answer you’re looking for, but if you’re supposed to translate it into a sentence it would be two moles of sodium bicarbonate(baking soda) decompose unto one mole of sodium carbonate(soda ash) plus one mole of water and one mole of carbon monoxide gas
8 0
2 years ago
Which body of water will have a greater influence on an area?
Andrei [34K]

Answer:

The correct option is A

Explanation:

Water from a river is used for many activities in a community. These activities could include (but not limited to) tourism, drinking for animals, local transport, irrigation for nearby farming, recreation (as in swimming), habitat for some living organisms among others. Rivers are not limited by what limits the influence of oceans such as taste (it's saltiness, which cannot be used in farming also) and wave current.

5 0
3 years ago
Is sodium laureth sulfate ionic or covalent?
stepladder [879]

Answer: Covalent

Explanation:

7 0
3 years ago
3. What is the mass of 5 moles of Hydrogen sulfate?I
solong [7]

Answer:

490

98 for 1 mole, Hence for 5 moles 5 X 98 =490.

Explanation:

Brainliest please?

3 0
3 years ago
if .709 j of heat is added to water and cause the temperature to go up by .036 degrees C what mass of water is present
liberstina [14]

Answer:

0.00471 grams H₂O

Explanation:

To determine the mass, you need to use the following equation:

Q = mcΔT

In this equation,

-----> Q = energy/heat (J)

-----> m = mass (g)

-----> c = specific heat capacity (J/g°C)

-----> ΔT = temperature change (°C)

The specific heat capacity of water is 4182 J/g°C. You can plug the given values into the equation and simplify to isolate "c".

Q = 0.709 J                            c = 4182 J/g°C

m = ? g                                   ΔT = 0.036 °C

Q = mcΔT                                                    <----- Equation

0.709 J = m(4182 J/g°C)(0.036 °C)            <----- Insert values

0.709 J = m(150.552)                                 <----- Multiply 4182 and 0.036

0.00471 = m                                              <----- Divide both sides by 150.552

8 0
1 year ago
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