Answer:
1.
work out the mean mode median and range
Explanation:
Answer:
5.71 g
Explanation:
Step 1: Write the balanced equation
2 K + Cl₂ ⇒ 2 KCl
Step 2: Calculate the moles corresponding to 12.0 g of KCl
The molar mass of KCl is 74.55 g/mol.
12.0 g × 1 mol/74.55 g = 0.161 mol
Step 3: Calculate the moles of Cl₂ needed to produce 0.161 moles of KCl
The molar ratio of Cl₂ to KCl is 1:2. The moles of Cl₂ needed are 1/2 × 0.161 mol = 0.0805 mol
Step 4: Calculate the mass corresponding to 0.0805 moles of Cl₂
The molar mass of Cl₂ is 70.91 g/mol.
0.0805 mol × 70.91 g/mol = 5.71 g
Answer:
d. Because those chemicals are easily made when CO2 reacts with water, forming H2CO3 (via carbonic anhydrase
Answer: 1.99 mol h20
Explanation:
you have 36.030 g, trying to get it into mols
to get from g to mols, use the molar mass (periodic table)
36.030 g h20 (1 mol/18.02g) = 1.99 mol h20
Answer:
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