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bixtya [17]
3 years ago
8

Zinc chloride (ZnCl2) and hydrogen (H2) are the products of a single replacement reaction. What are the reactants of this reacti

on? ? →ZnCl2 + H2 ZnHCl + HCl Zn + 2HCl H2 + Zn + Cl2
Chemistry
1 answer:
timurjin [86]3 years ago
4 0

Answer:

B Zn+2HCI

Explanation:

You might be interested in
Which property of metals allows aluminum to be flattened into thin sheets of aluminum foil?
Gnoma [55]

Answer:

malleability

Explanation:

3 0
3 years ago
A buffer is 0.282 m c6h5cooh(aq and 0.282 m na(c6h5coo(aq. calculate the ph after the addition of 0.150 moles of nitric acid to
Sindrei [870]
You have to use the Henderson-Hasselbalch equation. Keep in mind that because the Pka is given the equation changes form slightly:

PH = Pka + log[acid/base]

Step 1 (Figure out the concentrations):

0.282 M of Acid (C6H5OOH) - 0.150 M = 0.132 M of acid
0.282 M of Base (C6HCOO) + 0.150 M = 0.432 M of bas3

Step 2 (Plug into equation):

PH = Pka + log[acid/base]
PH = 4.20 + log[0.132 M/0.432 M]

PH = 3.69

7 0
3 years ago
Which has more thermal energy, 500g of ice or 500g of steam? explain your answer.
RUDIKE [14]
Steam because steam comes from water which the energy makes it into steam
7 0
3 years ago
Which of the following is NOT a characteristic of stars? A) Size B) temperature C) texture D) color
Lynna [10]

Answer:

C

Explanation:

Characteristics used to classify stars include color, temperature, size, composition, and brightness.

7 0
3 years ago
When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 14.4 g of carbon were burned in the presence of
Natasha2012 [34]

When carbon reacts with oxygen it forms CO2. This can depicted by the below equation.

C + O2→ CO2

It has been mentioned that when 14.4 g of C reacts with 53.9 g of O2, then 15.5 g of O2 remains unreacted. <u>This indicates that Carbon is the limiting reagent and hence the amount of CO2 produced is based on the amount of Carbon burnt.</u>

C + O2→ CO2

In the above equation , 1 mole of carbon reacts with 1 mole of O2 to produce 1 mole of CO2.

In this case 14.4 g of Carbon reacts with 53.9 of O2 to produce "x"g of CO2.

<u>No of moles = mass of the substance÷molar mass of the substance</u>

No of moles of carbon = 14.4 /12= 1.2 moles

No of moles of O2 = Mass of reacted O2/Molar mass of O2.

No of moles of O2 = (Total mass of O2 burned - Mass of unreacted O2)/32

No of moles of O2 = (53.9-15.5) ÷ 32 = 1.2 moles.

Hence as already discussed 1 mole of Carbon reacts with 1 mole of O2 to produce 1 mole of CO2. In this case 1.2 moles of carbon reacts with 1.2 moles of O2 to produce 1.2 moles of CO2.

Moles of carbon dioxide = Mass of CO2 produced /Molar mass of CO2

Mass of CO2 produced(x) = Moles of CO2 ×Molar mass of CO2

Mass of CO2 produced(x) = 1.2 x 44 = 52.8 g

<u>Thus 52.8 g of CO2 is produced.</u>

5 0
2 years ago
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