How does vapor pressure affect intermolecular forces.

Answers fast please Gets oxygen into your body and carbon dioxide out

yKpoI14uk [10]

B respiratory is correct

4 0

3 years ago

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The nonvolatile, nonelectrolyte estrogen (estradiol), C18H24O2 (272.40 g/mol), is soluble in chloroform CHCl3.

Artist 52 [7]

Answer: The molarity of solution is 0.274 M and the osmotic pressure of the solution is 6.70 atm

Explanation:

To calculate the molarity of the solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Given mass of estrogen = 13.5 g

Molar mass of estrogen = 272.40 g/mol

Volume of solution = 181 mL

Putting values in above equation, we get:

$\text{Molarity of solution}=\frac{13.5\times 1000}{272.40\times 181}\\\\\text{Molarity of solution}=0.274M$

Hence, the molarity of solution is 0.274 M

To calculate the osmotic pressure of the solution, we use the equation:

$\pi=iMRT$

where,

$\pi$ = osmotic pressure of the solution = ?

i = Van't hoff factor = 1 (for non-electrolytes)

M = molarity of solute = 0.274 M

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = temperature of the solution = 298 K

Putting values in above equation, we get:

$\pi=1\times 0.274mol/L\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 298K\\\\\pi=6.70atm$

Hence, the osmotic pressure of the solution is 6.70 atm

8 0

3 years ago

An unknown element, x, reacts with rubidium to form the compound rb2x. in other compounds this element also can accommodate up t

SVETLANKA909090 [29]

There are few elements that can form 12 electron rather than the usual 8. Therefore these are the possible answers:

Sulfur = 2Na + S --> Na2S 
Selenium = 2Na + Se --> Na2Se
Tellurium = 2Na + Te --> Na2Te

6 0

3 years ago

(A tablet containing calcium carbonate and fillers with a mass of 1.631 g was dissolved in HCl. After the fillers were filtered

FrozenT [24]

Answer:

1) 0.825 grams is the mass of pure calcium carbonate product collected at the end of the experiment.

2) The mass % calcium carbonate in the tablet is 50.58%.

3) The mass % of calcium in calcium carbonate is 40.00 %.

4) Mass of calcium in a tablet is 0.33 g.

Explanation:

Mass of tablet = 1.631 g

Mass of the watch glass = 46.719 g

Mass of the watch glass + mass of calcium carbonate = 47.544 g.

Mass of calcium carbonate = 47.544 g - 46.719 g = 0.825 g

0.825 grams is the mass of pure calcium carbonate product collected at the end of the experiment.

Mass of calcium carbonate = 0.825 g

Percentage of calcium in tablet:

$\%=\frac{\text{Mass of calcium carbonate }}{\text{Mass of tablet}}\times 100$

$\%=\frac{0.825 g}{1.631 g}\times 100=50.58\%$

The mass % calcium carbonate in the tablet is 50.58%.

Percentage of calcium in calcium carbonate :

Molar mass of calcium carbonate = 100 g/mol

Atomic mass of calcium = 40 g/mol

Percentage of calcium in calcium carbonate :

$\%=\frac{\text{atomic mass of calcium}}{\text{Molar mass of}CaCO_3}\times 100$

$\%=\frac{40 g/mol}{100 g/mol}\times 100=40.00\%$

The mass % of calcium in calcium carbonate is 40.00 %.

Mass of calcium carbonate = 0.825 g

The mass % of calcium in calcium carbonate is 40.00 %.

Mass of calcium in a tablet : x

$40.00\%=\frac{\text{Mass of calcium in a tablet}}{0.825 g}\times 100$

$x=40.00\times \frac{0.825 g}{100}=0.33 g$

Mass of calcium in a tablet is 0.33 g.

3 0

3 years ago

The volume of a single rhodium atom is 1.01×10-23 cm3. What is the volume of a rhodium atom in microliters?

Anni [7]

Answer: 1.01 x 10^20 microliters.

Explanation: volume is defined as a three-dimensional measure of space that comprises a length, a width and a height. In other words, we are asked to convert from one volumetric measure to another (cubic centimeters to microliters) —volume is measured in units of cubic centimeters in metric, cubic inches or cubic feet in English measurement.

If, 1 cm³ = 1000 uL (microliters) then,

1 uL - - - - - - - - - 0.001 cm³ = 1 x 10^-3 cm

x uL - - - - - - - - - 1.01×10^-23 cm³

Therefore,

x uL = 1.01 x 10^-23 cm³ / 0.001 cm³

x uL = 1.01 x 10^(-23 - - 3)

x uL = 1.01 x 10^( - 23 + 3)

x uL = 1.01 x 10^20

Which is to say that a single rhodium atom of volume 1.01 x 10^23 cm³ would occupy 1.01 x 10^20 microliters.

4 0

3 years ago