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r-ruslan [8.4K]
4 years ago
5

Which skier will have a greater potential energy? Justify your answer.

Chemistry
1 answer:
pochemuha4 years ago
6 0

Answer: Skier 1 will have more potential energy because he is higher than skier 2

Explanation: Gravitational potential energy is the energy possessed by a body by virtue of its position or height.

P.E=m\times g\times h

m= mass of the body

g= acceleration due to gravity

h= height of body

Thus if the masses of two bodies are same, the one with greater height possess greater potential energy.

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A sample of Br2 gas has a volume of 29.0L and a pressure of 1.50 atm. If the initial temperature of the gas is 23 °C, what volum
Jobisdone [24]

Answer:

V₂ = 22.84 L

Explanation:

Given data:

Initial volume = 20.0 L

Initial pressure = 1.50 atm

Initial temperature = 23 °C (23 +273 = 296 K)

Final temperature = 271°C (271+273 = 544 K)

Final pressure = 3.50 atm

Final volume = ?

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 1.50 atm × 29.0L ×544 K / 296 K × 3.50 atm

V₂ = 23664 atm .L. K / 1036 atm.K

V₂ = 22.84 L

5 0
3 years ago
For the reaction
sp2606 [1]

Answer:

n_{H_2}^{equilibrium}=0.393mol

Explanation:

Hello,

In this case, given the amounts of water and carbon dioxide we should invert the given reaction as hydrogen will be producted rather than consumed:

H_2O(g) + CO(g)\rightleftharpoons H_2(g) + CO_2(g)

Consequently, the equilibrium constant is also inverted:

Kc'=\frac{1}{Kc}=\frac{1}{0.534} =1.87

In such a way, we can now propose the law of mass action:

Kc'=\frac{[H_2][CO_2]}{[H_2O][CO]}

And we can express it in terms of the initial concentrations of the reactants and the change x due to the reaction extent:

Kc'=\frac{(x)(x)}{([H_2O]_0-x)([CO]_0-x)}=1.87

Thus, we compute the initial concentration which are same, since equal amount of moles are given:

[H_2O]_0=[CO]_0=\frac{0.680mol}{70.0L}=0.0097M

Hence, solving for x by using the quardratic equation or solver, we obtain:

x_1=0.00561M\\x_2=0.0361M

For which the correct value is 0.00561M since the other one will produce negative concentrations of water and carbon monoxide at equilibrium. Therefore, the number of moles of hydrogen at equilibrium for the same 70.0-L container turn out:

n_{H_2}^{equilibrium}=0.00561mol/L*70.0L=0.393mol

Best regards.

3 0
4 years ago
How many moles of nitrogen monoxide will be generated when 0.83 moles of nitrogen dioxide gas reacts with water?
wel
Answer C) 0.830 moles 

Please disgard what I am saying right now, I can't post since it needs 20 characters atleast. I hope this helped! :3
6 0
4 years ago
Read 2 more answers
The equilibrium constant for the formation of ammonia from nitrogen and hydrogen is 1.6 × 102. what is the form of the equilibri
Nimfa-mama [501]

Answer: The expression for equilibrium constant is \frac{[NH_3]^2}{[H_2]^3[N_2]}

Explanation: Equilibrium constant is the expression which relates the concentration of products and reactants preset at equilibrium at constant temperature. It is represented as k_c

For a general reaction:

aA+bB\rightleftharpoons cC+dD

The equilibrium constant is written as:

k_c=\frac{[C]^c[D]^d}{[A]^a[B]^b}

Chemical reaction for the formation of ammonia is:

N_2+3H_3\rightleftharpoons 2NH_3

k_c=1.6\times 10^2

Expression for k_c is:

k_c=\frac{[NH_3]^2}{[H_2]^3[N_2]}

1.6\times 10^2=\frac{[NH_3]^2}{[H_2]^3[N_2]}

8 0
3 years ago
Drag the correct label to the pictures. Each label can be used more than once. Classify the materials based on their composition
marta [7]

Answer:

I know, it's hard!!

Explanation:

7 0
3 years ago
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