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Maurinko [17]
3 years ago
9

The photo shows nervous tissue.

Chemistry
2 answers:
Margaret [11]3 years ago
8 0

Answer:

c. To send signals to control the body.

Explanation:

. It is responsible for coordinating and controlling many body activities. It stimulates muscle contraction, creates an awareness of the environment, and plays a major role in emotions, memory, and reasoning..

Nikolay [14]3 years ago
7 0

Answer:

The answer is c( to send signals to control the body)

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A certain second-order reaction (B→products) has a rate constant of 1.30×10−3 M−1⋅s−1 at 27 ∘C and an initial half-life of 224 s
soldier1979 [14.2K]

Answer:

       \large\boxed{\large\boxed{0.291M}}

Explanation:

By definition one <em>half-life</em> is the time to reduce the initial concentration to half.

For a <em>second order reaction </em>the rate law equations are:

              \dfrac{d[B]}{dt}=-k[B]^2

             \dfrac{1}{[B]}=\dfrac{1}{[B]_0}+kt

The <em>half-life</em> equation is:

            t_{1/2}=\dfrac{1}{k[A]_0}

Thus, substitute the<em> rate constant</em>  1.30\times 10^{-3}M^{-1}\cdot s^{-1} and the <em>half-life </em>time <em>224s</em> to find [A]₀:

           224s=\dfrac{1}{1.30\times10^{-3}M^{-1}\cdot s^{-1}[A]_0}

           [A]_o=0.291M

7 0
4 years ago
What is the percentage composition of each element in dinitrogen monoxide, N2O?
Kitty [74]

The correct answer is C :)

4 0
3 years ago
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The major use of carbon dioxide​
lidiya [134]

Answer:

Carbon dioxide is used as a refrigerant, in fire extinguishers, for inflating life rafts and life jackets, blasting coal, foaming rubber and plastics, promoting the growth of plants in greenhouses, immobilizing animals before slaughter, and in carbonated beverages.

3 0
3 years ago
Unicellular organisms reproduce using sexual or<br> asexual reproduction?
pav-90 [236]
Asexual Reproduction
8 0
3 years ago
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Given the balanced equation 2C4H10 + 13O2 → 8CO2 + 10H2O, how many moles of CO2 are produced when 14.9g of O2 are used?
Anna [14]

Answer: The number of moles of CO_2 produced are, 0.287 moles.

Explanation : Given,

Mass of O_2 = 14.9 g

Molar mass of O_2 = 32 g/mol

First we have to calculate the moles of O_2

\text{Moles of }O_2=\frac{\text{Given mass }O_2}{\text{Molar mass }O_2}

\text{Moles of }O_2=\frac{14.9g}{32g/mol}=0.466mol

Now we have to calculate the moles of CO_2

The balanced chemical equation is:

2C_4H_{10}+13O_2\rightarrow 10H_2O+8CO_2

From the reaction, we conclude that

As, 13 mole of O_2 react to give 8 moles of CO_2

So, 0.466 mole of O_2 react to give \frac{8}{13}\times 0.466=0.287 mole of CO_2

Therefore, the number of moles of CO_2 produced are, 0.287 moles.

3 0
3 years ago
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