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k0ka [10]
4 years ago
13

An element's atomic number is 45. How many protons would an atom of this element have?

Physics
2 answers:
STALIN [3.7K]4 years ago
5 0
Name:<span> Rhodium </span>
Symbol:<span> Rh </span>
Atomic Number:<span> 45 </span>
Atomic Mass:<span> 102.9055 amu </span>
Melting Point:<span> 1966.0 °C (2239.15 K, 3570.8 °F) </span>
Boiling Point:<span> 3727.0 °C (4000.15 K, 6740.6 °F) </span>
Number of Protons/Electrons:<span> 45 </span>
Number of Neutrons:<span> 58 </span>
Classification: Transition Metal 
Crystal Structure:<span> Cubic </span>
Density @ 293 K:<span> 12.41 g/cm</span>3 
Color:<span> silverish</span>
kaheart [24]4 years ago
3 0
It would have 45 protons, as the atomic number is equivalent to the amount of protons
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3 years ago
The phosphorus cycle is the biogeochemical cycle that describes the movement of phosphorus through the lithosphere,
ludmilkaskok [199]

A

most common source of phosphates in the soil is the weathering of the mineral apatite.

Explanation:

Apatite is a group of phosphate minerals like hydroxylapatite, fluorapatite, and chlorapatite. When apatite rocks weather, they release the phosphate minerals mainly in the form of PO₄ ³⁻ . These minerals become dissolved in water (hydrosphere), where they are readily available to plants and other organisms in the biosphere. The phosphates are taken up and used in biosynthesis. When these organisms die and become buried with sediments, the phosphate gets back to the lithosphere as sedimentary rock.

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5 0
3 years ago
Find the acceleration if a 32.5 N force is<br> used on an object that has a mass of<br> 128.6 kg.
Sholpan [36]

Answer:

Acceleration=3.95

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3 0
3 years ago
A sphere has surface area 1.25 m2, emissivity 1.0, and temperature 100.0°C. What is the rate at which it radiates heat into empt
Yuri [45]
The total power emitted by an object via radiation is:
P=A\epsilon \sigma T^4
where:
A is the surface of the object (in our problem, A=1.25 m^2
\epsilon is the emissivity of the object (in our problem, \epsilon=1)
\sigma = 5.67 \cdot 10^{-8} W/(m^2 K^4) is the Stefan-Boltzmann constant
T is the absolute temperature of the object, which in our case is T=100^{\circ} C=373 K

Substituting these values, we find the power emitted by radiation:
P=(1.25 m^2)(1.0)(5.67 \cdot 10^{-8}W/(m^2K^4)})(373 K)^4=1371 W = 1.4 kW
So, the correct answer is D.
6 0
3 years ago
What runs all the way around the house but never moves?
amm1812
<span>A fence runs all the way around the house but never moves.</span>
6 0
3 years ago
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