All categories

3 years ago

HELP !!!!!

Physics

2 answers:

prohojiy [21]3 years ago

6 0

Answer:D

Explanation:

s2008m [1.1K]3 years ago

6 0

Answer:

C. The slope of the line

Explanation:

The slope of the trend line is independent (this is a density of the body by the way). The volume of the body depends on the mass, and the mass depends on the volume

You might be interested in

A student is studying simple harmonic motion of a spring. She conducts an experiment where she measures the amplitude and period

myrzilka [38]

Answer:

5.9*10^{-4}m

Explanation:

to find the uncertainty of the displacement it is necessary to compute the uncertainty for the angular frequency:

$\omega=\frac{2\pi}{T}=\frac{2\pi}{0.40s}=15.707rad/s\\\\\frac{d \omega}{\omega}=\frac{dT}{T}\\\\d\omega=\omega \frac{dT}{T}=(15.707rad/s)\frac{0.020s}{0.40s}=0.785rad/s$

then, you can calculate the uncertainty in angular displacement:

$\theta=\omega t\\\\\frac{d\theta}{\theta}=\sqrt{(\frac{d\omega}{\omega})^2+(\frac{dt}{t})^2}\\\\d\theta=\theta\sqrt{(\frac{d\omega}{\omega})^2+(\frac{dt}{t})^2}=0.0422$

finally, by using:

$y=Acos(\omega t)\\\\dy=dAcos(\omega t)d(\omega t)=(dA)cos(\theta)d\theta=(0.002m)cos(0.785)(0.0422)\\\\dy=5.9*10^{-4}m$

7 0

3 years ago

At t= 10 s, a particle is moving from left to right with a speed of 5.0 m/s. At t=20 s, the particle is moving right to left wit

Shkiper50 [21]

Answer

given,

at time t = 10 s moving from left to right speed of particle = 5 m/s

at t = 20 s moving from right to left speed of particle is = 8 m/s

a) acceleration

$a = \dfrac{\Delta V}{\Delta t}$

$a = \dfrac{-8-(5)}{20-10}$

a = -1.3 m/s²

b) using equation of motion

v = u + at

5 = u - 1.3 × 10

u = 5 + 13

u = 18 m/s

c) v = u + at

0 = 18 - 1.3t

$t = \dfrac{18}{1.30}$

t = 13.85 s

4 0

3 years ago

A 2.7-kg cart is rolling along a frictionless, horizontal track towards a 1.1-kg cart that is held initially at rest. The carts

olga2289 [7]

Answer:

Part a)

P = 8.23 kg m/s

Part b)

v = 3.05 m/s

Explanation:

Part a)

momentum of cart 1 is given as

$P_1 = m_1v_1$

$P_1 = (2.7)(3.7) = 9.99 kg m/s$

Momentum of cart 2 is given as

$P_2 = m_2v_2$

$P_2 = (1.1)(-1.6) = -1.76 kg m/s$

Now total momentum of both carts is given as

$P = P_1 + P_2$

$P = 8.23 kg m/s$

Part b)

Since two carts are moving towards each other due to mutual attraction force and there is no external force on two carts so here momentum is always conserved

so here we will have

$P_i = P_f$

$(2.7 kg)v = 8.23$

$v = 3.05 m/s$

3 0

3 years ago

A boat floats south on the Amazon River at a speed of 6 m/s south. The boat and passengers have a combined mass of 540 kg.

Anna [14]

A. The momentum of the boat, given the data is 3240 Kg.m/s

B. The new velocity of the boat is 11.93 m/s

<h3>What is momentum? </h3>

Momentum is defined as the product of mass and velocity. It is expressed as

Momentum = mass × velocity

<h3>What is impulse? </h3>

This is defined as the change in momentum of an object.

Impulse = change in momentum

Impulse = final moment – Initial momentum

Imulpse = m(v - u)

<h3>How to determine the momentum</h3>

Mass = 540 Kg
velocity = 6 m/s
Momentum = ?

Momentum = mass × velocity

Momentum = 540 × 6

Momentum = 3240 Kg.m/s

<h3>How to determine the new velocity</h3>

Mass = 540 Kg
Initial velocity = 6 m/s
Impulse = 3200 kg·m/s
Final velocity =?

Imulpse = m(v - u)

3200 = 540 × (v - 6)

Divide both sides by 540

v - 6 = 3200 / 540

v - 6 = 5.93

Collect like terms

v = 5.93 + 6

v = 11.93 m/s

Learn more about momentum:

brainly.com/question/250648

#SPJ1

5 0

2 years ago

Define Mechanical energy. Using an example of the pendulum, explain how kinetic and potential energy relate to the mechanical en

mamaluj [8]

It has previously been mentioned that there is a relationship between work and mechanical energy change. Whenever work is done upon an object by an external force (or nonconservative force), there will be a change in the total mechanical energy of the object. If only internal forces are doing work (no work done by external forces), then there is no change in the total amount of mechanical energy. The total mechanical energy is said to be conserved. In this part of Lesson 2, we will further explore the quantitative relationship between work and mechanical energy in situations in which there are no external forces doing work.

The quantitative relationship between work and the two forms of mechanical energy is expressed by the following equation:

The equation illustrates that the total mechanical energy (KE + PE) of the object is changed as a result of work done by external forces. There are a host of other situations in which the only forces doing work are internal or conservative forces. In such situations, the total mechanical energy of the object is not changed. The external work term cancels from the above equation and mechanical energy is conserved. The previous equation is simplified to the following form:

In these situations, the sum of the kinetic and potential energy is everywhere the same. As the potential energy is increased due to the stretch/compression of a spring or an increase in its height above the earth, the kinetic energy is decreased due to the object slowing down. As the potential energy is decreased due to the return of a spring to its rest position or a decrease in height above the earth, the kinetic energy is increased due to the object speeding up. We would say that energy is transformed or changes its form from kinetic energy to potential energy (or vice versa); yet the total amount present is conserved - i.e., always the same.

5 0

3 years ago