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kvasek [131]
3 years ago
11

A sample of glass bead weighs 34.5g. The beads are heated to 100.0C in a boiling water bath and poured into a beaker containing

100.0g H2O at 25C. when thermal equilibrium is reached, the temperature of the glass and the water is 29.9C. what is the specific heat of the glass
Chemistry
1 answer:
zaharov [31]3 years ago
3 0
The heat lost by the beads is equal to the heat gained by the water. The specific heat capacity of water is 4.18 joules/gram. "w" will denote water's property and "b" will denote the beads' properties.
mw x Cpw x ΔTw = -mb x Cpb x ΔTb
100 x 4.18 x (29.9 - 25) = 34.5 x Cpb x (100 - 29.9)

Cpb = 0.84 joules/gram
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Explanation:

The equation for the reaction is :

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From the balanced equation, we obtain :

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From the question, we obtain:

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Mb = conc. of base = 0.25M.

We solve for the conc. of the acid using:

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Divide both side by 0.105. We have

Ma = (0.25 x 0.0357 x 2) / 0.105

Ma = 0.17M

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Answer:

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Explanation:

Hello,

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