Answer:
B - The energy of reactants is conserved.
D - the nuclei of atoms changes completely ( if that's the option)
<span>134 ml
First, let's determine how many moles of oxygen we have.
Atomic weight oxygen = 15.999
Molar mass O2 = 2*15.999 = 31.998 g/mol
We have 3 drops at 0.050 ml each for a total volume of 3*0.050ml = 0.150 ml
Since the density is 1.149 g/mol, we have 1.149 g/ml * 0.150 ml = 0.17235 g of O2
Divide the number of grams by the molar mass to get the number of moles
0.17235 g / 31.998 g/mol = 0.005386274 mol
Now we can use the ideal gas law. The equation
PV = nRT
where
P = pressure (1.0 atm)
V = volume
n = number of moles (0.005386274 mol)
R = ideal gas constant (0.082057338 L*atm/(K*mol) )
T = Absolute temperature ( 30 + 273.15 = 303.15 K)
Now take the formula and solve for V, then substitute the known values and solve.
PV = nRT
V = nRT/P
V = 0.005386274 mol * 0.082057338 L*atm/(K*mol) * 303.15 K / 1.0 atm
V = 0.000441983 L*atm/(K*) * 303.15 K / 1.0 atm
V = 0.133987239 L*atm / 1.0 atm
V = 0.133987239 L
So the volume (rounded to 3 significant figures) will be 134 ml.</span>
NOTE question is incorrect: The question should be:
<span>How many moles of KCLO4 can be produced with 3.45 moles of KCl. Assume all other reactants are in excess.
.......................................................................................................................
The reaction involving formation of KClO4 is
NaClO4 + KCl </span>→ KClO4 + NaCl
From above reaction, it can be seen that 1 mole of NaClO4 reacts with 1 mole of KCl to generate 1 mole of KClO4
Thus, if all other reactant are in excess, 3.45 moles of KCl will react with 3.45 moles of NaClO4 to form 3.45 moles of KClO4.
Answer:
The mass
Explanation:
the mass grams of 3.75 × 10 21 atoms of Li is
40. 21 atom of Li
Answer:
C
Explanation:
Just look at the reactants.
2AgCl + BaBr2
The first reactant is made of 2 elements.
The second reactant is made of 2 elements.
It can't be a decomposition. At this level there is only one reactant made of 2 elements. Something like
2MgO ===> 2Mg + O2
is a decomposition. One compound breaking down into 2 elements Mg and O.
It can't be a combustion. One of the reactants in a combustion is oxygen. Those equations look like
C3H8 + 5O2 ==> 3CO2 + 4H2O
That would be what a combustion looks like
It can't be a single replacement. They look like
Mg + CuO ===> Cu + MgO
There are elements on both sides of the reaction.
that leaves a double replacement which I wrote about how you distinguish it.
