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Artemon [7]
2 years ago
6

Human impact on one system leads to changes in more of Earth’s systems.   Please select the best answer from the choices provide

d T F
Physics
2 answers:
faust18 [17]2 years ago
8 0

Answer;

The above statement is true

Human impact on one system leads to changes in more of Earth’s systems.  

Explanation;

Events can occur naturally, such as an earthquake or a hurricane, or they can be caused by humans, such as an oil spill or air pollution. An event can cause changes to occur in one or more of the spheres, and/or an event can be the effect of changes in one or more of Earth's four spheres.

Human impact on one system leads to changes in more of Earth’s systems because things like carbon and methane emissions affect the environment, which affects all plant and animal life.  

My name is Ann [436]2 years ago
5 0
Hello there, the correct answer is:

True.
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A 2.0-kg ball has a momentum of 25kg.m/s what is the ball's speed?
Reil [10]

We know, momentum = mass * speed

25kgm/s = 2 kg * s

s = 25/2 = 12.5 m/s

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3 years ago
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How much of the Moon is always illuminated one time? Explain your answer.
Natalija [7]

Answer:

50% of it .

Explanation:

50% of it is illuminated by the Sun.

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2 years ago
Which of the following is not a part of dalton s atomic theory?
Alex777 [14]
<span>c. atoms are always in motion..............</span>
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3 years ago
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A parallel-plate capacitor has square plates that have edge length equal to 1.20×102cm and are separated by 1.00 mm. It is conne
lora16 [44]

Answer:

Energy stored in the capacitor will be 1.835\times 10^{-6}J

Explanation:

We have given edge length of capacitor = 1.2\times 10^2cm=1.2m

So area A = 1.2×1.2 = 1.44 m^2

Separation is given as d  1 mm = 10^{-3}m

We know that capacitance is given by C=\frac{\epsilon _0A}{d}=\frac{8.85\times 10^{-12}\times 1.44}{10^{-3}}=12.744\times 10^{-9}F

Voltage is given as V = 12 volt

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3 0
3 years ago
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A geosynchronous Earth satellite is one that has an orbital period of precisely 1 day. Such orbits are useful for communication
koban [17]

Answer:

r = 4.24x10⁴ km.  

     

Explanation:

To find the radius of such an orbit we need to use Kepler's third law:

\frac{T_{1}^{2}}{T_{2}^{2}} = \frac{r_{1}^{3}}{r_{2}^{3}}

<em>where T₁: is the orbital period of the geosynchronous Earth satellite = 1 d, T₂: is the orbital period of the moon = 0.07481 y, r₁: is the radius of such an orbit and r₂: is the orbital radius of the moon = 3.84x10⁵ km.                           </em>                              

From equation (1), r₁ is:

r_{1} = r_{2} \sqrt[3] {(\frac{T_{1}}{T_{2}})^{2}}                            

r_{1} = 3.84\cdot 10^{5} km \sqrt[3] {(\frac{1 d}{0.07481 y \cdot \frac{365 d}{1 y}})^{2}}      

r_{1} = 4.24 \cdot 10^{4} km      

Therefore, the radius of such an orbit is 4.24x10⁴ km.

I hope it helps you!

3 0
3 years ago
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