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laiz [17]
3 years ago
14

A student wearing a frictionless roller skates on a horizontal is pushed by a friend with a constant force of 55N. How far must

the student be pushed, starting from rest, so that her final kinetic energy is 362 J
Physics
1 answer:
umka21 [38]3 years ago
3 0

Answer:

6.58m

Explanation:

The kinetic energy = Workdone on the roller

Workdone = Force * distance

Given

KE = Workdone = 362J

Force = 55N

Required

Distance

Substitute into the formula;

Workdone = Force * distance

362 = 55d

d = 362/55

d = 6.58m

Hence the student must push at a distance of 6.58m

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A 523.2-W space heater is designed for operation in Germany, where household electrical outlets supply 230 V (rms) service. What
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Answer:

power = 142.4 W

Explanation:

power of heater in Germany (P₁) = 523.2 W

power of heater in America (P₂) = ?

outlet voltage in Germany (V₁) = 230 V

outlet voltage in America (V₂) = 120 V

  • While in Germany, power = \frac{V₁^{2}}{R}

         523.2 = \frac{230^{2}}{R}

         R = 101.1

  • While in America, also power = \frac{V₂^{2}}{R}

         using the value of R gotten above

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6 0
3 years ago
Laura sees a horse pulling a buggy. She wonders how it can accelerate if the action of the horse pulling the cart would cause an
cricket20 [7]

Answer:

The net forces exerted on the horse and cart are not the same, so they are not balanced forces.

Explanation:

Using newton laws,

ΣF = ma

The two forces acting on the body is the forward force by the horse and the frictional force opposing the forward force

F-Fr= ma

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F=ma+Fr

So the forward (by horse) is more than the opposite reaction (by cart).

The only time the forward force and the opposite reaction are the same is when a=0, I.e, the body is not moving at all or the body is moving at constant velocity.

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