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erma4kov [3.2K]
3 years ago
13

A simple pendulum with a length of 2 m oscillates on the Earth's surface. What is the period of oscillations?

Physics
1 answer:
katrin [286]3 years ago
5 0

Answer:

Period, T = 27.84 seconds

Explanation:

Given the following data;

Length of pendulum = 2m

We know that acceleration due to gravity on earth is equal to 9.8 m/s²

To find the period of oscillation of the simple pendulum;

Mathematically, it is given by the formula;

Period, T = 2 \pi \sqrt {lg}

Substituting into the equation, we have;

Period, T = 2 * 3.142 * \sqrt {2*9.8}

Period, T = 6.284 * \sqrt {19.6}

Period, T = 6.284 * 4.43

Period, T = 27.84 seconds

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