There are different options here but all of them work by approximating and assuming.
i) that the boulder is above ground.
ii) that the bottom surface of the boulder is known.
iii) the shape of the boulder is taken into account.
The most accurate way is measuring it by displacement method but the boulder is immovable hence the volume can be calculated by measuring the boulder or a waterproof box to be built around the boulder and calculate the volume occupied by boulder.
All the above methods are estimating methods.
*Another way to find the density is through specific gravity.
S.G = <u>Density</u><u> </u><u>of</u><u> </u><u>object</u>
Density of water
If the material that makes the boulder is known that is if it's stone or a mineral then the specific gravity can be found.
If the boulder is purely rock then S.G lies between 3 - 3.5 and the density of water is known thus the density of the boulder can be found without moving the boulder.
This is what I think after correction and allthe best!
Answer:
'A ball is thrown straight up with an initial speed of 12 m/s_ What are the velocity and acceleration when it is at the top of its trajectory? Select all apply. v=12 mls a = 0 v =-12 mls a = 9.8 m/s2 Oa=-9.8 m/s2'
Explanation:
I look it up
Hope this helps
Answer: 33.3 m/s^2
Explanation:
Here we need to use the second Newton's law.
F = m*a
Force equals mass times the acceleration.
Here we know that the force is F = 4000 N, and the mass is 120kg, then the acceleration must be:
4000 N = 120kg* a
a = (4000/120) m/s^2 = 33.3 m/s^2
Answer:
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Answer:
Her angular momentum does not change.
Explanation:
Conservation of angular momentum: It states that there is no change in the angular momentum when no torque outside the system is applied to the body.
In the given problem, an ice skater spins her arm outstretched. She pulls her arms in towards her body.
The angular momentum of an ice skaters remains same as the there is no external torque applied on an ice skater. The initial angular momentum and the final angular momentum of the given system are same. Therefore, the angular momentum is conserved.
Therefore, her angular momentum does not change.
