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3 years ago

Find the voltage across the 15 Q resistor. [?] V No links please

Physics

1 answer:

Margaret [11]3 years ago

4 0

Answer:

Explanation:

same idea as before Liam, first, find the parallel resistance in 35 || 20

(35*20) / (35+20) = 700 / 55 = 12.727272 ohms

now add the 12.727272 + 15 = 27.727272 ohms total resistance

V = IR

10 = I * 27.727272

10 / 27.727272 = I

0.360655 = I

V = IR (again, but across the 15 ohm resistor)

V = 0.360655 * 15

V = 5.4098

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Is it accurate to say that galaxies take up most of the volume of space? Why or why not?

RUDIKE [14]

Answer:

ntergalactic space takes up most of the volume of the universe, but even galaxies and star systems consist almost entirely of empty space.

Explanation:

so to be exact galixes do make up most of the volume of space because galaxies are what make up space!

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2 years ago

A truck moving at 13.3 m/s hits a concrete wall. As a result of the collision, a 6-kg wrench moves forwards and strikes the wall

Naddik [55]

Answer:

Explanation:

The velocity of the wrench must be equal to the velocity of the truck . So momentum of the wrench before it hits the wall

= mv = 6 x 13.3 = 79.8 kg m /s

If resisting force of wall be F , impulse on the wrench = F x time

= F x .07

Impulse = change in momentum of the wrench = mv - 0 = mv = 79.8 kgm/s

So F x .07 = 79.8

F = 1140 N .

8 0

3 years ago

2. A particular planet has a moment of inertia of 9.74 × 1037 kg•m2 and a mass of 5.98 × 1024 kg. Based on these values, what is

mash [69]

Answer:

$6.38\cdot 10^6 m$

Explanation:

The planet can be thought as a solid sphere rotating around its axis. The moment of inertia of a solid sphere rotating arount the axis is

$I=\frac{2}{5}MR^2$

where

M is the mass

R is the radius

For the planet in the problem, we have

$M=5.98\cdot 10^{24} kg$

$I=9.74\cdot 10^{37} kg\cdot m^2$

Solving the equation for R, we find the radius of the planet:

$R=\sqrt{\frac{5I}{2M}}=\sqrt{\frac{5(9.74\cdot 10^{37}}{2(5.98\cdot 10^{24}}}=6.38\cdot 10^6 m$

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3 years ago

Near the top of the Citigroup Center building in New York City, there is an object with mass of 4.00 ✕ 105 kg on springs that ha

jasenka [17]

Explanation:

It is given that,

Mass of an object, $m=4\times 10^5\ kg$

(a) Time period of oscillation, T = 2.4 s

The formula for the time period of spring is given by :

$T=2\pi \sqrt{\dfrac{m}{k}}$

Where

k is the force constant

$k=\dfrac{4\pi ^2 m}{T^2}$

$k=\dfrac{4\pi ^2 \times 4\times 10^5}{(2.4)^2}$

$k=2.74\times 10^6\ N/m$

(b) Displacement in the spring, x = 2.2 m

Energy stored in the spring is given by :

$U=\dfrac{1}{2}kx^2$

$U=\dfrac{1}{2}\times 2.74\times 10^6\ N/m\times (2.2\ m)^2$

$U=6.63\times 10^6\ J$

Hence, this is the required solution.

7 0

4 years ago

How is our magnetic field made?

Grace [21]

Answer:

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Explanation:

Hope this helps!

7 0

3 years ago

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