Answer:
Explanation:
Heat energy given out by the soup
= C_v x ( t₂ - t₁ )
= 33 x ( 340 - 300)
= 1320 J
This heat is given to Carnot engine . Efficiency of engine
= (340 - 300 ) / 340
= 40 / 340
2 / 17
This fraction of total heat given is converted into useable work by the engine.
Answer:117.6joules
Explanation:
Mass(m)=2kg
Height(h)=6m
Acceleration due to gravity(g)=9.8m/s^2
Potential energy(PE)=?
PE=m x g x h
PE=2 x 9.8 x 6
PE=117.6joules
Answer:
HENCE (3) IS ANSWER
Explanation:
α =ΔL/(LO×Δ T) or ΔL= α(LO×Δ T)
HERE ΔL IS CHANGE IN LENGTH, Lo is original length , α is coefficient of linear expansion , Δ T is change in temperature
α= 11 x 10 ^-6/°C , Δ T = 19-20 = -1°C
hence
ΔL= 11 x 10 ^-6×10×-1
= - 11×10^-5
MINUS SIGN SHOWS SHORTER
HENCE (3) IS ANSWER
The answer is b
300,000 km
Answer:
10kg
Explanation:
Let PE=potential energy
PE=196J
g(gravitational force)=9.8m/s^2
h(change in height)=2m
m=?
PE=m*g*(change in h)
196=m*9.8*2
m=10kg
