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Wittaler [7]
4 years ago
13

Why do the densities of most substances decrease with an increase in temperature?

Physics
1 answer:
taurus [48]4 years ago
7 0
Because density is related to activity of particles, the higher the activity level (the faster they're moving, and distance between them) the less dense they are. for example, H2O in a solid the particles are close together with minimum movement and it exists as ice, but when heat is applied the particles become more active and move more decreasing the density becoming liquid water, then when excessive heat is applied the same occurs and it becomes gas steam 
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Which of the following statements are true? Check all that apply.
BigorU [14]
<span><u>Answers.</u>
a. The electric field between the plates of a parallel capacitor is uniform
b. A capacitor is a device that stores potential energy and electric charges.
c. The capacitance of a capacitor depends upon its structure.
<u>
Explanation </u>
Capacitor is a device that is used to store electric charge. The capacitance that can be stored in a capacitor depend on area of overlap of the plates, dielectric used and distance between the two plates of a parallel capacitor.
From the choices given in the question the one that applies are:
a. The electric field between the plates of a parallel capacitor is uniform
b. A capacitor is a device that stores potential energy and electric charges.
c. The capacitance of a capacitor depends upon its structure.  
</span>
4 0
4 years ago
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Tectonic plates move due to _____ forces.
wel
<span>Tectonic plates move because they are floating on top of the liquid mantle. The mantle itself moves due to convection currents: hot rock rises, gives off some heat, then falls. This creates vast swirls of moving liquid rock under the crust of the earth, which jostles the plates of crust on top.
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6 0
3 years ago
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One of the specific goals of of environmental analysis is:____________
Allushta [10]

Answer:

a: To provide organized information, for the development of the organization's internal analysis, mission, vision, values, and strategy.

Explanation:

Environmental analysis is a process in business wherein the internal and external factors that can affect a business are examined so as to help improve the organization's goals and strategies. The internal analysis serves as a guide to checkmate the organization and to see if they have adopted the right strategies that suit their external environment.

Competitors in the external environment can have a huge impact on the business. So the internal workings of the organization should align with the external factors. The organized information would also be useful in forecasting the growth of the business.          

8 0
4 years ago
A 13.5 μF capacitor is connected to a power supply that keeps a constant potential difference of 22.0 V across the plates. A pie
-BARSIC- [3]

a) 3.27\cdot 10^{-3} J

b) 11.60\cdot 10^{-3} J

c) 8.33\cdot 10^{-3} J

Explanation:

a)

The energy stored in a capacitor is given by

U=\frac{1}{2}CV^2

where

C is the capacitance of the capacitor

V is the potential difference across the plates of the capacitor

For the capacitor in this problem, before insering the dielectric, we have:

C=13.5 \mu F = 13.5\cdot 10^{-6}F is its capacitance

V = 22.0 V is the potential difference across it

Therefore, the initial energy stored in the capacitor is:

U=\frac{1}{2}(13.5\cdot 10^{-6})(22.0)^2=3.27\cdot 10^{-3} J

b)

After the dielectric is inserted into the plates, the capacitance of the capacitor changes according to:

C'=kC

where

k = 3.55 is the dielectric constant of the material

C is the initial capacitance of the capacitor

Therefore, the energy stored now in the capacitor is:

U'=\frac{1}{2}C'V^2=\frac{1}{2}kCV^2

where:

C=13.5\cdot 10^{-6}F is the initial capacitance

V = 22.0 V is the potential difference across the plate

Substituting, we find:

U'=\frac{1}{2}(3.55)(13.5\cdot 10^{-6})(22.0)^2=11.60\cdot 10^{-3} J

C)

The initial energy stored in the capacitor, before the dielectric is inserted, is

U=3.27\cdot 10^{-3} J

The final energy stored in the capacitor, after the dielectric is inserted, is

U'=11.60\cdot 10^{-3} J

Therefore, the change in energy of the capacitor during the insertion is:

\Delta U=11.60\cdot 10^{-3}-3.27\cdot 10^{-3}=8.33\cdot 10^{-3} J

So, the energy of the capacitor has increased by 8.33\cdot 10^{-3} J

8 0
3 years ago
Which energy position do electrons generally want to be in?the ground state
Kisachek [45]
Ground state, since electrons want to be in the lowest energy position as possible, which is closer to the nucleus of the atom.
4 0
4 years ago
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