Answer:
The rate at which velocity changes with respect to a change in time is called. acceleration.
Explanation:
Answer:
Explanation:
PE = mgh = 60(9.8)(2.0) = 1176 J
Answer:
The final position made with the vertical is 2.77 m.
Explanation:
Given;
initial velocity of the ball, V = 17 m/s
angle of projection, θ = 30⁰
time of motion, t = 1.3 s
The vertical component of the velocity is calculated as;
![V_y = Vsin \theta\\\\V_y = 17 \times sin(30)\\\\V_y = 8.5 \ m/s](https://tex.z-dn.net/?f=V_y%20%3D%20Vsin%20%5Ctheta%5C%5C%5C%5CV_y%20%3D%2017%20%5Ctimes%20sin%2830%29%5C%5C%5C%5CV_y%20%3D%208.5%20%5C%20m%2Fs)
The final position made with the vertical (Yf) after 1.3 seconds is calculated as;
![Y_f = V_yt - \frac{1}{2}g t^2\\\\Y_f = (8.5 \times 1.3 ) - (\frac{1}{2} \times 9.8 \times 1.3^2)\\\\Y_f = 11.05 \ - \ 8.281\\\\Y_f = 2.77 \ m](https://tex.z-dn.net/?f=Y_f%20%3D%20V_yt%20%20-%20%5Cfrac%7B1%7D%7B2%7Dg%20t%5E2%5C%5C%5C%5CY_f%20%3D%20%288.5%20%5Ctimes%201.3%20%29%20-%20%28%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%209.8%20%5Ctimes%201.3%5E2%29%5C%5C%5C%5CY_f%20%3D%2011.05%20%5C%20-%20%5C%208.281%5C%5C%5C%5CY_f%20%3D%202.77%20%5C%20m)
Therefore, the final position made with the vertical is 2.77 m.
Answer:
Inertia is directly proportional to mass of an object. Therefore, when the force of inertia increases the mass also increases, and when it decreases the mass also decreases.
Explanation:
Answer:
K_a = 8,111 J
Explanation:
This is a collision exercise, let's define the system as formed by the two particles A and B, in this way the forces during the collision are internal and the moment is conserved
initial instant. Just before dropping the particles
p₀ = 0
final moment
p_f = m_a v_a + m_b v_b
p₀ = p_f
0 = m_a v_a + m_b v_b
tells us that
m_a = 8 m_b
0 = 8 m_b v_a + m_b v_b
v_b = - 8 v_a (1)
indicate that the transfer is complete, therefore the kinematic energy is conserved
starting point
Em₀ = K₀ = 73 J
final point. After separating the body
Em_f = K_f = ½ m_a v_a² + ½ m_b v_b²
K₀ = K_f
73 = ½ m_a (v_a² + v_b² / 8)
we substitute equation 1
73 = ½ m_a (v_a² + 8² v_a² / 8)
73 = ½ m_a (9 v_a²)
73/9 = ½ m_a (v_a²) = K_a
K_a = 8,111 J