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TEA [102]
3 years ago
5

In October 1997, Andy Green broke the sound barrier on land in a jet-powered car. Green's car had accelerated from rest to 763 m

i/h (341 m/s) over a 5.0-mi (8047-m) stretch. Assuming constant acceleration, over what time interval had he reached the top speed
Physics
1 answer:
wolverine [178]3 years ago
4 0

Answer: the time interval Green had to reached the top speed is 47.2 secs

Explanation:

Given the data in the question;

first we determine Green's acceleration.

from third equation of motion, v² - u² = 2as

a = v² - u² / 2s

we substitute,

a = ( (341 m/s)² - (0)² ) / 2(8047)

a = (116281 - 0) / 16094

a = 7.23 m/s²

Now we determine the time interval need to reach top or maximum speed,

v = u + at

at = v - u

t = (v - u) / a

so we substitute

t = (341 - 0) / 7.23

t = 341 / 7.23

t = 47.2 secs

Therefore, the time interval Green had to reached the top speed is 47.2 secs

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Answer:

33.61°

Explanation:

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Or ,

n = c/v.

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c is the speed of light in air = 3.0 × 10⁸ m/s

So,  

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n = 1.31

Using Snell's law as:

n_i\times {sin\theta_i}={n_r}\times{sin\theta_r}

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Angle of refraction = sin^{-1}0.5536 = 33.61°

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             F = eE

where,    e = charge of the proton

According to the Newton's second law of motion, the net force acting on the proton is as follows.

                       F = ma

                 a = \frac{eE}{m}

                    = \frac{e(\frac{\sigma}{2 \epsilon_{o}})}{m}

                    = \frac{e \sigma}{2m \epsilon_{o}}

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              v_{f} = v_{i} + at

                     = (0 m/s) + \frac{e \sigma}{2 m \epsilon_{o}}t

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