Answer:
The answer is first one 1...
Answer:
The torque experienced by the new loop is 1/4 of that experienced by the old loop.
Explanation:
The torque τ = IBASinΦ
Assuming the direction of current flow through the loop is perpendicular to that of the magnetic field, SinΦ = Sin90° = 1 and
τ = IBA. With the current flowing through the loop and the magnetic field remaining the same for both cases, then
τ ∝ A. The area is equal to πD² where D is the diameter so
τ ∝ D². Let the old loop have a diameter D. Using the same length of wire, the act of doubling the loop (making 2 turns of wire) reduces the diameter by a factor of 1/2. So the new diameter is D/2
τ ∝ (D/2)² which means that τ ∝ D²/4. So the new torque is 1/4 the old torque.
Vector quantities have magnitude as well as direction but scalar have only magnitude.
