All categories

3 years ago

3.4 x 10-25 kg = ? microounces

Chemistry

1 answer:

Thepotemich [5.8K]3 years ago

8 0

Answer: 1.2 x 10^-17 microounces

Explanation:

Ounce = 28.5G microounce = 28.5*10^-6g

3.4*10^-25 kg = 3.4*10^-22 g = (3.4/2.85)*10^(-22+5) = 1.2*10-17

You might be interested in

What change would most likely decrease the rate of a chemical reaction? A) maintaining a temperature close to room temperature B

Nutka1998 [239]

Answer:

D) cooling of the reaction mixture

Explanation:

Increase in temperature speedens the rate of a chemical reaction

5 0

3 years ago

PLEASE HELP DUE TONIGHT THANK YOU

Sav [38]

Answer:

check the attached image. hope it helps

Explanation:

a. What does mol/L mean? mol/L means Molar Concentration

b. Describe in your own words how mol/L compares to grams/liter. (similarities and differences)

Similarities: mol/L and grams/liter both are units of concentration.

Differences:

mol/L concentration says how many moles of solute are present in 1L of solution.

grams/liter concentration says how many grams of solute are present in 1L of solution.

3. Describe at least 2 ways in the simulation to change each of the parameters:

a. Volume of solution= evaporating or adding more water

b. amount of solute=reducing the water or evaporating more water

c. Concentration of solute in solution = evaporating or adding more solute

3 0

2 years ago

A piece of wood has a mass of 36g and measures 3cm X 6cm X 4cm. What is the density of the wood? Would the piece of wood float o

Fudgin [204]

Answer:

Explanation:

The density is

1.1 g c m 3 .

4 0

3 years ago

When energy transforms, which of the following does it produce?

Aliun [14]

motion

Explanation:

it works in our daily life

8 0

3 years ago

The partial pressure of CO2 gas in a bottle of carbonated water is 4.60 atm at 25 ºC. How much CO2 gas (in g) will be released f

frutty [35]

If the partial pressure of CO₂ in a bottle of carbonated water decreases from 4.60 atm to 1.28 atm, the mass of CO₂ released is 0.265 g.

The partial pressure of CO₂ gas in a bottle of carbonated water is 4.60 atm at 25 ºC. We can calculate the concentration of CO₂ using Henry's law.

$C = k \times P = \frac{1.65 \times 10^{-3} M }{atm} \times 4.60 atm = 7.59 \times 10^{-3} M$

We can calculate the mass of CO₂ in 1.1 L considering its molar mass is 44.01 g/mol.

$\frac{7.59 \times 10^{-3} mol}{L} \times 1.1 L \times \frac{44.01 g}{mol} = 0.367 g$

Now, we will repeat the same procedure for a partial pressure of 1.28 atm.

$C = k \times P = \frac{1.65 \times 10^{-3} M }{atm} \times 1.28 atm = 2.11 \times 10^{-3} M$

$\frac{2.11 \times 10^{-3} mol}{L} \times 1.1 L \times \frac{44.01 g}{mol} = 0.102 g$

The mass of CO₂ released will be equal to the difference in the masses at the different pressures.

$m = 0.367 g - 0.102 g = 0.265 g$

If the partial pressure of CO₂ in a bottle of carbonated water decreases from 4.60 atm to 1.28 atm, the mass of CO₂ released is 0.265 g.

Learn more: brainly.com/question/18987224

The partial pressure of CO₂ gas in a bottle of carbonated water is 4.60 atm at 25 ºC. How much CO₂ gas (in g) will be released from 1.1 L of the carbonated water when the partial pressure of CO2 is lowered to 1.28 atm? At 25 ºC, the Henry’s law constant for CO₂ dissolved in water is 1.65 x 10⁻³ M/atm, and the density of water is 1.0 g/cm³.

5 0

3 years ago