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PSYCHO15rus [73]
3 years ago
14

1.C3H8 + O2 --> H2O + CO2 (5 Points) Balanced O Unbalanced

Chemistry
1 answer:
Vedmedyk [2.9K]3 years ago
5 0

Answer:

Unbalanced

Explanation:

The balanced equation would be:

C3H8 + <u>  5  </u>O2  ---> <u>  4  </u>H2O + <u>  3   </u>CO2

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What is the molarity of a solution prepared by dissolving 8 grams of BaCl2 in enough
olga55 [171]

Answer:

Explanation:

molar mass of BaCl2 = 208.23

mol of BaCl2 = 8/208.22

mol of BaCl2 = 0.03841905

Molarity = 0.03841905/0.450

Molarity = 0.085 M

6 0
2 years ago
Which place on earth would be likely to have the most humidity due to water vapor in the atmosphere? Moscow, Russia Toronto, Can
mel-nik [20]

Answer:

Nassau, Bahamas

Explanation: The Bahamas are close to the equator so it has more heat which means higher water evaporation which leads to a higher humidity than the other places.

6 0
3 years ago
(14.1.50) 0.03 mol of helium are enclosed in a cylinder with a piston which maintains a constant pressure in the helium. Initial
icang [17]

Answer:

a) 0.210 j /k

b) 0.032 j/k

Explanation:

Find the attachment for solution

3 0
4 years ago
What is the pH of a 3.40 mM of acetic acid, 500 mL in which 50 mL of 1.00 M NaOAc has been added? Ka HOAc is 1.8 x 10-5? What pe
Deffense [45]

Answer:

a) pH = 4.213

b) % dis = 2 %

Explanation:

Ch3COONa → CH3COO- + Na+

CH3COOH ↔ CH3COO- + H3O+

∴ Ka = 1.8 E-5 = ([ CH3COO- ] * [ H3O+ ]) / [ CH3COOH ]

mass balance:

⇒ <em>C</em> CH3COOH + <em>C</em> CH3COONa = [ CH3COOH ] + [ CH3COO- ]

<em>∴ C </em>CH3COOH = 3.40 mM = 3.4 mmol/mL * ( mol/1000mmol)*(1000mL/L)

∴ <em>C</em> CH3COONa = 1.00 M = 1.00 mol/L = 1.00 mmol/mL

⇒ [ CH3COOH ] = 4.4 - [ CH3COO- ]

charge balance:

⇒ [ H3O+ ] + [ Na+ ] = [ CH3COO- ] + [ OH- ]....is negligible [ OH-], comes from water

⇒ [ CH3COO- ] = [ H3O+ ] + 1.00

⇒ Ka = (( [ H3O+ ] + 1 )* [ H3O+ ]) / ( 3.4 - [ H3O+])) = 1.8 E-5

⇒ [ H3O+ ]² + [ H3O+ ] = 6.12 E-5 - 1.8 E-5 [ H3O+ ]

⇒ [ H3O+ ]² + [ H3O+ ] - 6.12 E-5 = 0

⇒  [ H3O+ ] = 6.12 E-5 M

⇒ pH = - Log [ H3O+ ] = 4.213

b) (% dis)* mol acid = <em>C</em> CH3COOH = 3.4

∴ mol CH3COOH = 500*3.4 = 1700 mmol = 1.7 mol

⇒ % dis = 3.4 / 1.7 = 2 %

7 0
3 years ago
Whats the correct order of these?
Igoryamba
1109, 5.9 * 10 squared, -0.041, -4.2 times 10 to the -3, and -7.6 times 10 to the -5
Hope this helps
3 0
3 years ago
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