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jarptica [38.1K]
3 years ago
12

Which substance is always a product when an Arrhenius acid in an aqueous solution reacts with an Arrhenius base in an aqueous so

lution?
(1) HBr (3) KBr
(2) H2O (4) KOH
Chemistry
2 answers:
meriva3 years ago
6 0

Answer: Option (B) is the correct answer.

Explanation:

According to Arrhenius, acid are the substance that produce hydrogen ions when dissolved in a solution.

For example, HBr \rightarrow H^{+} + Br^{-} shows that HBr is an Arrhenius acid.

Whereas Arrhenius bases are the substances that produce hydroxide ions when dissolved in a solution.

For example,  KOH \rightarrow K^{+} + OH^{-} shows that KOH is an Arrhenius base.

Therefore, when an Arrhenius acid in an aqueous solution reacts with an Arrhenius base in an aqueous solution then following reaction occurs.

                  HBr + KOH \rightarrow KBr + H_{2}O

Thus, we can conclude that out of the given options, KBr is the product.

svetoff [14.1K]3 years ago
3 0
The answer is (2). The question only ask the production of acid reacts with base. The acid has H+ ion and base has OH- ion. When they react, the production will always contain H2O.
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Give the oxidation state of sulfur in (d) H₂S ;
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The correct answer is -2 oxidation state.

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5 0
2 years ago
The electron in a hydrogen atom, originally in level n = 8, undergoes a transition to a lower level by emitting a photon of wave
timofeeve [1]

Explanation:

It is given that,

The electron in a hydrogen atom, originally in level n = 8, undergoes a transition to a lower level by emitting a photon of wavelength 3745 nm. It means that,

n_i=8

\lambda=3745\ nm

The amount of energy change during the transition is given by :

\Delta E=R_H[\dfrac{1}{n_f^2}-\dfrac{1}{n_i^2}]

And

\dfrac{hc}{\lambda}=R_H[\dfrac{1}{n_f^2}-\dfrac{1}{n_i^2}]

Plugging all the values we get :

\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{3745\times 10^{-9}}=2.179\times 10^{-18}[\dfrac{1}{n_f^2}-\dfrac{1}{8^2}]\\\\\dfrac{5.31\times 10^{-20}}{2.179\times 10^{-18}}=[\dfrac{1}{n_f^2}-\dfrac{1}{8^2}]\\\\0.0243=[\dfrac{1}{n_f^2}-\dfrac{1}{64}]\\\\0.0243+\dfrac{1}{64}=\dfrac{1}{n_f^2}\\\\0.039925=\dfrac{1}{n_f^2}\\\\n_f^2=25\\\\n_f=5

So, the final level of the electron is 5.

4 0
3 years ago
1. Nuclear decay by alpha particle emission is more common in atoms of elements that:
11111nata11111 [884]

Answer 1) Option a) have an atomic number greater than 83


Explanation : Nuclear decay by alpha particle emission is more common in atoms of elements that have an atomic number greater than 83. Nuclear reactions occurs with the elements which have mass number more than 200.


Answer 2) Option D) He^{4}_{2}


Explanation : In the given nuclear reaction of helium;


He^{3}_{2} + He^{3}_{2}  -----> He^{4}_{2} + 2 P^{1}_{1}


Two helium isotopes combines to give another helium isotope with emission of a proton (P).


Answer 3) Option D) The products are more radioactive than the reactants.


Explanation : The major drawback of a nuclear fission reaction to be used as an reliable energy source is that it usually produces the products which are found to be more radioactive than the reactants.


Answer 4) Option D) All of the above concerns.


Explanation : Nuclear reactions are usually very harmful in nature. It raises many concerns about the waste disposal that is generated from the reaction. It also requires safe operation for the working nuclear plants. It can also be misused for nuclear weapon proliferation. Hence, the answer is all of the above.


Answer 5) False.


Explanation : The energy output of the Sun and other stars is a result of fusion reactions among hydrogen nuclei. In fusion reactions usually additions takes place.


Answer 6) Option B) The "missing" mass has been converted to energy


Explanation : The total mass of a helium nucleus not equal to the mass of its individual parts because the missing mass has to be converted into energy.


Answer 7) Option A) less than the mass-energy of the products


Explanation : In a nuclear reaction, the mass-energy of the reactants is generally less than that of the mass-energy of the products because some energy has to be generated while the reaction is progressing.


Answer 8) Option D) 9.00 X 10^{17} J


Explanation : The calculation of the mass of 10.0 kilograms is completely converted into energy.


E = m X C^{2} formula can be used.


here m = 10 Kg and C = 3 X 10^{8} m/s



E = 10 X 3 X 10^{8} = 9.00 X 10^{17} J.


Answer 9) Option C) 3.60 X 10^{17} J.


Explanation : For calculation of energy for mass of 4 Kg


we can use the Einstein's formula,



E = m X C^{2}


where m = 4 Kg and C = C = 3 X 10^{8} m/s


E = 4 X 3 X 10^{8} = 3.60 X 10^{17} J.


Answer 10) False.


Einstein's formula for the conversion of mass and energy, to find the energy, multiply the mass by the speed of light squared.


E = m X C^{2}

3 0
4 years ago
Imagine that Ana has a block made of pure gold. If she cuts this block into two equal pieces, pick the statement that best descr
dimaraw [331]

Answer : The correct statement is:

The density of each piece is the same as that of the original block.

Explanation :

Intensive property : It is defined as a property of substance which does not change as the amount of substance changes.

Examples: Temperature, refractive index, density, hardness, etc.

According to question, if Ana has a block made of pure gold and she cuts this block into two equal pieces then the density of each piece is the same as that of the original block because density is an intensive property that does not changes until and unless material is changed.

That means density remains same as that of the original piece.

Hence, the correct statement is the density of each piece is the same as that of the original block.

6 0
4 years ago
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