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2 years ago

What is the overall process of balancing an equation?

Chemistry

1 answer:

monitta2 years ago

3 0

Answer:

You need to make sure the number of atoms of each element on the reactant side is equal to the number of atoms of each element on the product side. In order make both sides equal, you will need to multiply the number of atoms in each element until both sides are equal. :)

You might be interested in

Easons for the dense packing in metals <br>

Firdavs [7]

Explanation:

Typically, only one element is present, so all atomic radii are the same. -Metallic bonding is not directional. -Nearest neighbor distances tend to be small in order to lower bond energy.

7 0

2 years ago

How many 2-tablespoon doses are in 4 bottles of medication containing 16 ounces each?

Dima020 [189]

1 tablespoon = 0.5 ounces

We are required to find for 2 table spoons.

2 table spoons = 2 x 0.5 = 1 ounce.

Each bottle has 16 ounce.

Number of bottles = 4

So total number = 4 x 16 = 64 ounces.

Number of 2 table spoons = $\frac{64 ounce}{1 ounce}$

= 64

Thus there are 64 2-tablespoon doses are in 4 bottles of medication containing 16 ounces each.

8 0

3 years ago

Iron will most likely react with which of the following elements?

gtnhenbr [62]

Answer:

bromine (Br)

Explanation: Iron enters into a reaction with substances of different classes, and interacts with oxygen, carbon, phosphorus, halogens (bromine, iodine, fluorine and chlorine), and also nitrogen. These are not all the reactions of iron – this metal reacts with many elements.

5 0

3 years ago

If acetic acid is the only acid that vinegar contains (ka=1.8×10−5), calculate the concentration of acetic acid in the vinegar.

kicyunya [14]

Ethanoic (Acetic) acid is a weak acid and do not dissociate fully. Therefore its equilibrium state has to be considered here.

$CH_{3}COOH \ \textless \ ---\ \textgreater \ H^{+} + CH_{3}COO^{-}$

In this case pH value of the solution is necessary to calculate the concentration but it's not given here so pH = 2.88 (looked it up)

pH = 2.88 ==> $[H^{+}]$ = $10^{-2.88}$ = 0.001 $moldm^{-3}$

The change in Concentration Δ $[CH_{3}COOH]$ = 0.001 $moldm^{-3}$

  CH3COOH H+ CH3COOH
Initial   $moldm^{-3}$      $x$ 0 0

Change $moldm^{-3}$ -0.001 +0.001 +0.001

Equilibrium $moldm^{-3}$ $x$ - 0.001 0.001 0.001


Since the $k_{a}$ value is so small, the assumption
$[CH_{3}COOH]_{initial} = [CH_{3}COOH]_{equilibrium}$ can be made.

$k_{a} = [tex]= 1.8*10^{-5} = \frac{[H^{+}][CH_{3}COO^{-}]}{[CH_{3}COOH]} = \frac{0.001^{2}}{x}$

Solve for x to get the required concentration.

note: 1.)Since you need the answer in 2SF don&t round up values in the middle of the calculation like I've done here.

2.) The ICE (Initial, Change, Equilibrium) table may come in handy if you are new to problems of this kind

Hope this helps!

8 0

3 years ago

What type of epithelium would be most suited for high levels of diffusion and filtration?

NemiM [27]

Sorry the answer might be a little late but it would be <span>Simple squamous</span>

6 0

2 years ago