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Ghella [55]
3 years ago
5

If you place 2 moles of NaCL in a beaker and then add enough water to have a final volume of 0.5 liters, what is the molarity of

the solution?
Chemistry
1 answer:
julia-pushkina [17]3 years ago
3 0

Answer:

The molarity of the solution is 4M

Explanation:

Molarity is defined as the amount of moles of solute present in one liter of solution. So the molarity of any solution can be found by dividing the moles of solute between the volume in liters of the solution.

For this case we have:

M=\frac{2\:moles\:NaCl}{0.5\:L\:solution} =4M

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If 35.0 mL of water in a graduated cylinder is displaced by 8.00 mL
sdas [7]

Answer:

<h2>0.52 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}\\

From the question

volume = final volume of water - initial volume of water

volume = 35 - 8 = 27 mL

We have

density =  \frac{14}{27}  \\  = 0.518518...

We have the final answer as

<h3>0.52 g/mL</h3>

Hope this helps you

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Write the manufacturing process of oxygen gas from liquid air​
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Answer:

Production of liquid oxygen from air Oxygen is generated by liquefaction of atmospheric air in the air separation unit (ASU). Cryogenic technique is the most commonly used for producing liquid oxygen for industrial and medical applications .

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If a system is left to change spontaneously, in what state will it end?
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Answer:

The state with the lowest possible energy consistent with the state of maximum disorder

so letter A

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The following molecular equation represents the reaction that occurs when aqueous solutions of silver(I) nitrate and calcium chl
dsp73

Answer:

Ag+(aq) + Cl-(aq) —> AgCl(s)

Explanation:

2AgNO3(aq) + CaCl2(aq) —>2AgCl(s) + Ca(NO3)2(aq)

The balanced net ionic equation for the reaction above can be obtained as follow:

AgNO3(aq) and CaCl2(aq) will dissociate in solution as follow:

AgNO3(aq) —> Ag+(aq) + NO3-(aq)

CaCl2(aq) —> Ca2+(aq) + 2Cl-(aq)

AgNO3(aq) + CaCl2(aq) –>

2Ag+(aq) + 2NO3-(aq) + Ca2+(aq) + 2Cl-(aq) —> 2AgCl(s) + Ca2+(aq) + 2NO3-(aq)

Cancel out the spectator ions i.e Ca2+(aq) and 2NO3- to obtain the net ionic equation.

2Ag+(aq) + 2Cl-(aq) —> 2AgCl(s)

Divide through by 2

Ag+(aq) + Cl-(aq) —> AgCl(s)

The, the net ionic equation is

Ag+(aq) + Cl-(aq) —> AgCl(s)

4 0
3 years ago
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