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g100num [7]
3 years ago
14

How many meters are in 924 millimeters? equality statement: 1 m = 1000 mm.?

Mathematics
1 answer:
xenn [34]3 years ago
8 0
<span>1 m = 1000 mm
924 mm=924/1000
924mm=0.924m

Answer is..
0.924m</span>
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A boathouse costs $2500 a month to operate, and it spends $600 each
Sever21 [200]

Answer:

P(n)=300n-2500

Step-by-step explanation:

The fixed cost to operate the boathouse is $2500/month. It also has a cost of $600/month for every boat it docks.  

If n boats are docked, then the total monthly cost is expressed as

C=2500+600n

The boathouse charges $900/month for every boat docked. The revenue for n boats will be

R=900n

The profit function can be constructed by subtracting revenue and cost

P(n)=900n-(2500+600n)=300n-2500

7 0
3 years ago
Read 2 more answers
Prove that: (12^13–12^12+12^11)(11^9–11^8+11^7) is divisible by 3, 7, 19, and 37. The answer should be like: x^b*3*7*19*37. Also
n200080 [17]

Answer:

Step-by-step explanation:

Given (12^13–12^12+12^11)(11^9–11^8+11^7),

(12^13–12^12+12^11)(11^9–11^8+11^7) =

[(12^12)12 – 12^12 + 12^11][(11^8)11 – 11^8 + 11^7)

[(12^12)(12 – 1) + 12^11][(11^8)(11 – 1) + 11^7] =

(12^12(11) + 12^11)(11^8(10) + 11^7) =

(12^11(12x11) + 12^11)(11^7(11x10) + 11^7) =

[(12^11)(12x11 + 1)][(11^7)(11x10 + 1)] =

[(12^11)x(11^7)](12x11 + 1)(11x10 + 1) =

[(12^11)x(11^7)](133 x 111) =

[(12^11)x(11^7)](133 x 111) =

[(12^11)x(11^7)](14763) =

[(12^11)x(11^7)](3x7x19x37)

From here, it is clear that the given number is divisible by 3, 7, 19 and 37.

6 0
3 years ago
PLOT THE POINT [1.5 -2] PLS HELP ASAP
m_a_m_a [10]

Answer: 1.5 will be on the point of 1 but just a little bit higher. -2 will be plotted exactly on -2

Step-by-step explanation:

8 0
2 years ago
Evaluate the expression 5a + 5b. Let a = -6 and b = -5.
GrogVix [38]
<span>Evaluate the expression 5a + 5b. Let a = -6 and b = -5.

n = 5a + 5b
n = 5(-6) + 5(-5)
n = -30 + -25
n = -55

Hope this helps

</span>
8 0
3 years ago
Read 2 more answers
For any perfect square trinomial (quadratic), the constant term (last term) must be positive.
Ronch [10]

Answer:

For the perfect square trinomial (quadratic) i.e. \left(x\:+\:3\right)^2, the constant term (last term) is positive.

Step-by-step explanation:

"Perfect square trinomials" are termed as the quadratics that are the outcomes of squaring binomials.

For example:

\left(x\:+\:3\right)^2

\mathrm{Apply\:Perfect\:Square\:Formula}:\quad \left(a+b\right)^2=a^2+2ab+b^2

a=x,\:\:b=3

=x^2+2x\cdot \:3+3^2

=x^2+6x+9

Therefore, for the perfect square trinomial (quadratic) i.e. \left(x\:+\:3\right)^2, the constant term (last term) is positive.

5 0
3 years ago
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