Answer : The pH of the solution is, 5.24
Explanation :
First we have to calculate the volume of 
Formula used :
where,
are the initial molarity and volume of 
.
are the final molarity and volume of .
We are given:
Putting values in above equation, we get:
Now we have to calculate the total volume of solution.
Total volume of solution = Volume of + Volume of
Total volume of solution = 160.0 mL + 1086.79 mL
Total volume of solution = 1246.79 mL
Now we have to calculate the Concentration of salt.
Now we have to calculate the pH of the solution.
At equivalence point,
![pOH=\frac{1}{2}[pK_w+pK_b+\log C]](https://tex.z-dn.net/?f=pOH%3D%5Cfrac%7B1%7D%7B2%7D%5BpK_w%2BpK_b%2B%5Clog%20C%5D)
![pOH=\frac{1}{2}[14+4.87+\log (0.0437)]](https://tex.z-dn.net/?f=pOH%3D%5Cfrac%7B1%7D%7B2%7D%5B14%2B4.87%2B%5Clog%20%280.0437%29%5D)
Thus, the pH of the solution is, 5.24
Answer:
when mass is 1×10⁴ Kg then density is 5 g/cm³.
when mass is 104 Kg then density is 5.2 × 10⁻² g/ cm³.
Explanation:
Density:
Density is equal to the mass of substance divided by its volume.
Units:
SI unit of density is Kg/m3.
Other units are given below,
g/cm3, g/mL , kg/L
Formula:
D=m/v
D= density
m=mass
V=volume
Symbol:
The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.
Given data:
mass = 1×10⁴ Kg
volume= w ×l× h = 1×2× 1 = 2 m³
density = ?
first of all we will convert the given volume meter cube to cm³:
we know that
2×1000000 = 2 × 10⁶ cm³
Now we will convert the mass into gram.
1 Kg = 1000 g
1×10⁴ × 1000 = 1 ×10⁷ g
Now we will put the values in the formula,
d = m/v
d = 1 ×10⁷ g / 2×10⁶ cm³
d = 0.5 × 10¹ g/cm³
or
d = 5 g/cm³
If mas is 104 Kg:
104 × 1000 = 104000 g
d= m/v
d = 104000 g / 2×10⁶ cm³
d= 52000 ×10⁻⁶ g/ cm³
d= 5.2 × 10⁻² g/ cm³
Answer:
xy (-b+c+q) is the answer to this
> 2,000
mL of a 5.0 × 10–5% (w/v) sucrose solution
5.0 × 10–3
g/mL * 2000 mL * (1 mol / 342.30 g) = 0.0292 mol
<span>
> 2,000 mL of a 5.0 ppm sucrose solution</span>
5 grams /
1000000 mL * 2000 mL* (1 mol / 342.30 g) = 0.0000292 mol
<span>
> 20 mL of a 5.0 M sucrose solution </span>
5.0 M *
0.020 L = 0.1 mol
Answer:
<span>2,000 mL
of a 5.0 ppm sucrose solution</span>
There will be chemical reaction(equation4Na+02--2Na20
