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Kisachek [45]
3 years ago
6

Friction, conduction, and induction are all methods through which _______ can be transferred.

Chemistry
2 answers:
Ugo [173]3 years ago
8 0

Friction, conduction, and induction are all methods through which energy can be transferred.

Hope that helps.

GREYUIT [131]3 years ago
4 0

Answer:

It is charge.

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calcium and strontium are close to one another on thw oeriodic table. what do you know about their ionization energies ,their el
Firdavs [7]

Both Ca and Sr are in Group 2 of the Periodic Table, with Sr below Ca (see image)..

<em>Ionization energies </em>

They are both metals, so they have relatively <em>low ionization energies</em>.

Sr is below Ca in the Group, so Sr has the lower ionization energy.

<em>Electron configurations </em>

Their electron configurations both end in <em>ns²</em>.

For example, the electron configuration of Ca is [Kr]<em>4s²</em> and that of Sr is [Kr]<em>5s²</em>.

<em>Physical chsrscteristics: </em>

  • metallic lustre
  • malleable
  • ductile
  • good conductors of heat and electricity

<em>Chemical characteristics</em>

Both metals react with

• <em>Hydrogen</em> to form hydrides: M + H₂ ⟶ MH₂

• <em>Oxygen</em> to form oxides: 2M + O₂ ⟶ 2MO

• <em>Nitrogen</em> to form nitrides: 3M + N₂ ⟶ M₃N₂

• <em>Halogens</em> to form halides: M + X₂ ⟶ MX₂

• <em>Water</em> to displace hydrogen: M + 2H₂O ⟶ M(OH)₂ + H₂

4 0
3 years ago
If cats take over the world, will you make them extinct or be their slave.
prisoha [69]

Answer:

Make them go instinct

Explanation:

No one wants cats taking over the whole world

3 0
4 years ago
I need help with this someone help
allochka39001 [22]

Answer:

1. Element is Ca

2. 20 electrons

3. 2 valence electrons

4. 4 energy levels

6 0
2 years ago
Consider the reaction: I2(g)+Cl2(g)⇌2ICl(g) Kp= 81.9 at 25 ∘C. Calculate ΔGrxn for the reaction at 25 ∘C under each condition: -
scoray [572]

Answer:

Part 1: - 1.091 x 10⁴ J/mol.

Part 2: - 1.137 x 10⁴ J/mol.

Explanation:

Part 1: At standard conditions:

At standard conditions Kp= 81.9.

∵ ΔGrxn = -RTlnKp

∴ ΔGrxn = - (8.314 J/mol.K)(298.0 K)(ln(81.9)) = - 1.091 x 10⁴ J/mol.

Part 2: PICl = 2.63 atm; PI₂ = 0.324 atm; PCl₂ = 0.217 atm.

For the reaction:

I₂(g) + Cl₂(g) ⇌ 2ICl(g).

Kp = (PICl)²/(PI₂)(PCl₂) = (2.63 atm)²/(0.324 atm)(0.217 atm) = 98.38.

∵ ΔGrxn = -RTlnKp

∴ ΔGrxn = - (8.314 J/mol.K)(298.0 K)(ln(98.38)) = - 1.137 x 10⁴ J/mol.

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3 years ago
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