Question

The density of oxygen gas is 1.429 × 10–3 g/cm3 at standard conditions. What would be the percent error of the average of two separate experimental determinations measuring 1.112 × 10–3 g/cm3 and 1.069 × 10–3 g/cm3? (To solve this problem, average the two readings before calculating the percent error.)

Answer 1

Answer:

0.034%

Explanation:

First, let's calculated the average density (da) of the two experimental, which the sum of them divided by 2:

$da = \frac{1.112x10^{-3} + 1.069x10^{-3}}{2}$

da = 1.090x10⁻³ g/cm³

The relative error is given by the difference of the correct value and the avarege, divided by the correct value:

$e = \frac{1.429x10^{-3} - 1.090x10^{-3}}{1.429x10^{-3}}$

e = 3.39x10⁻⁴ x 100%

e = 0.034%