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3 years ago

What is the molar mass of magnesium chloride, MgCl2?

Chemistry

1 answer:

Verizon [17]3 years ago

5 0

95.3g/mole

Explanation:

To find the molar mass of substance, we sum the atomic masses of the number of atoms present.

The molar mass of a compound is grams per mole mass of the atoms it contains.

For MgCl₂;

Atomic mass of Mg = 24.3g/mol

Cl = 35.5g/mol

Molar mass = 24.3 + 2(35.5) = 95.3g/mole

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Molar mass brainly.com/question/2861244

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Sodium hydroxide (NaOH) and elemental sodium (Na)

Olegator [25]

Answer:

If the question is which can make a buffer, then NH3, NH4Cl should be correct. Because Ammonium (NH4) is conjugate acid of NH3 so they can form an equilibrium which is basically a buffer whose purpose is to resist pH change.

Explanation:

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3 years ago

A balloon is filled to a volume of 1.50 L with 3.00 mol of gas at 25 C. with pressure and temperature held constant, what will b

bixtya [17]

Answer:

3.2L

Explanation:

PV=nRT

since pressure and temperature are held constant we have V=nR

R is a constant also,

Thus; $\frac{v1}{n1}=\frac{v2}{n2}$

v1=1.5L , n1=3mol, n2=1.4mol

$\frac{1.5}{3}=\frac{v2}{1.4}$

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v2=3.2L

7 0

3 years ago

What is the correct answer please

Anestetic [448]

Answer:

I think it's the second answer --If you increase the acidity..

I hope answer I can answer your question!

7 0

3 years ago

Provide 3 examples of substances that are mixtures and list the substances in them.

babunello [35]

Salt and water
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3 0

2 years ago

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What is the molarity of a solution made from 325.4 g of AlCl3 (MM 133.34 g/mol) to make 500.0 mL?

NISA [10]

Answer : The molarity of a solution is, 4.88 M

Explanation : Given,

Mass of $AlCl_3$ = 325.4 g

Volume of solution = 500.0 mL

Molar mass of $AlCl_3$ = 133.34 g/mole

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

$\text{Molarity}=\frac{\text{Mass of }AlCl_3\times 1000}{\text{Molar mass of }AlCl_3\times \text{Volume of solution (in mL)}}$

Now put all the given values in this formula, we get:

$\text{Molarity}=\frac{325.4g\times 1000}{133.34g/mole\times 500.0mL}=4.88mole/L=4.88M$

Therefore, the molarity of a solution is, 4.88 M

6 0

3 years ago

Read 2 more answers