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frosja888 [35]
4 years ago
9

What products result from mixing aqueous solutions of Cr(NO3)2(aq) and NaOH(aq)? Question 10 options: Cr(OH)2(s), Na+(aq), and N

O3−(aq) Cr(OH)2(s) and NaNO3(s) Cr2(OH)2(aq) and NaNO3(aq) Cr(OH)2(aq) and NaNO3(s) Cr(OH)2(s), N2(g), and H2O(l)
Chemistry
1 answer:
Alecsey [184]4 years ago
4 0

Answer:

Cr(OH)2(s), Na+(aq), and NO3−(aq)

Explanation:

Let is consider the molecular equation;

2NaOH(aq) + Cr(NO3)2(aq) -----> 2NaNO3(aq) + Cr(OH)2(s)

This is a double displacement or double replacement reaction. The reacting species exchange their partners. We can see here that both the sodium ion and chromium II ion both exchanged partners and picked up each others partners in the product.

Sodium ions and nitrate ions now remain in the solution while chromium II hydroxide which is insoluble is precipitated out of the solution as a solid hence the answer.

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A solution is made by mixing 0.82 grams of sodium acetate, 1 mL of 12 M acetic acid (pKa=4.76) and water to give a final volume
kompoz [17]

Answer:

This solution acts as an efficient buffer

Explanation:

the pH of a buffer solution can be described like this: pH=pKa+log\frac{[base]}{[acid]}

[acid]=[acetic acid]=1mL.\frac{12mol}{1000mL} . \frac{1}{1L} = 0.012M

[base]=[sodium acetate]=0.82g.\frac{1mol}{82g} .\frac{1}{1l} = 0.01M

replacing, pH=4.76+log\frac{0.01M}{0.012M} =4.84

If we add an acid, pH will decrease a little bit and if we add a base, pH wil increase a little bit.

lets supose that we change the rate by increasing [base] to 0.1, then

pH=4,76+log\frac{0.1}{0.012} = 5.68

and now lets supose that we increase [acid] to 0.1 pH=4.76+log\frac{0.01}{0.1} = 3.76

Big changes in concentration of base or acid doesn´t produce big changes in pH, in that way the mix of sodium acetate with acetic acid is a good buffer solution.

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