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Studentka2010 [4]
3 years ago
14

How many helium-filled balloons would it take to lift a person? Assume the person has a mass of 76 kg and that each helium-fille

d balloon is spherical with a diameter of 35 cm .
Physics
1 answer:
sergij07 [2.7K]3 years ago
7 0

Answer:

15200 i think im not 100% sure but i tried doing the math

Explanation:

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What do the three variables (f,m, a) in the equation mean?
Anna [14]

Answer:

f=force m=mass and a=acceleration

7 0
3 years ago
A 2.2 kg model rocket is shot straight up in the air from the ground, with an initial velocity of 36.4 m/s. The rocket reaches i
alexandr1967 [171]

Answer:

Explanation:

Ignoring friction, the initial kinetic energy will convert to maximum potential energy at its highest point.

PE = KE

mgh = ½mv²

    h = v²/2g

    h = 36.4²/ (2(9.81))

    h = 67.53109...

    h = 67.53 m

3 0
2 years ago
A container is filled to a depth of 19.0 cm with water. On top of the water floats a 31.0-cm-thick layer of oil with specific gr
IceJOKER [234]

Answer:

Absolute pressure of the oil will be 102822.8 Pa  

Explanation:

We have given height h = 31 cm = 0.31 m

Acceleration due to gravity g=9.8m/sec^2

Specific gravity of oil = 0.600

So density of oil \rho =0.6\times 1000=600kg/m^3

We know that absolute pressure is given by P=P_0+\rho gh, here P_0=1.01\times 10^5Pa

So absolute pressure will be equal to P=1.01\times 10^5+600\times 9.8\times 0.31=102822.8Pa

So absolute pressure of the oil will be 102822.8 Pa

6 0
3 years ago
Use a(t) = -32 feet per second per second as the acceleration due to gravity. (Neglect air resistance.) -With what initial veloc
Kitty [74]

Answer:

u= 187.61 ft/s

Explanation:

Given that

g= - 32 ft/s²

The maximum height ,h= 550 ft

Lets take the initial velocity = u ft/s

We know that

v²=u² + 2 g s

v=final speed ,u=initial speed ,s=height

When the object reach at the maximum height then the final speed of the object will become zero.

That is why

u²= 2 x 32 x 550

u²= 35200

u= 187.61 ft/s

That is why the initial speed will be 187.61 ft/s

7 0
3 years ago
Read 2 more answers
5. A 905 kg test car travels around a 3.04 km circular track. If the magnitude of the centripetal force is 2100 N. What is the c
balu736 [363]

Answer:

Explanation:

The equation for centripetal force is

F=\frac{mv^2}{r}. We have all the values we need except for the radius. We have the circumference of the circle, though, so we will solve for the radius using that and the fact that C = 2πr:

3.04 = 2(3.1415)r and

r = .484 m, to the correct number of sig fig's.

Now that we have everything we need and isolating the v NOT squared:

v=\sqrt{\frac{rF}{m} } and filling in:

v=\sqrt{\frac{(.484)(2100)}{905} } . This answer will need 2 sig fig's since 2100 has 2 sig fig's in it. That means that the velocity of the test car is

1.1 m/sec

8 0
3 years ago
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