Answer: If a reaction produces a gas such as oxygen or carbon dioxide, there are two ways to measure the reaction rate: using a gas syringe to measure the gas produced, or calculating the reduction in the mass of the reaction solution.
Explanation:
https://courses.lumenlearning.com/introchem/chapter/measuring-reaction-rates/#:~:text=If%20a%20reaction%20produces%20a,mass%20of%20the%20reaction%20solution.
This is the site I got it from. I hope this helps.
This question does not contain the structures of the molecules. The structures in Daylight SMILES format are:
I. C1=CC=CC=C1C(=O)C
II. C1=CC=CC=C1CC=O
III. C1=CC(C)=CC=C1C=O
IV. C1=CC=CC=C1CCC
V. C1=CC=CC=C1C(C)C
The structures are also attached
Answer:
The structure of compound IV is consistent with the information obtained analysis
Proposed structures for the ions with m/z values of 120, 105,77 and 43 are (also attached):
C1=CC=CC=C1C(=[OH0+])C |^1:7|
C1C([CH0+]=O)=CC=CC=1
C1[CH0+]=CC=CC=1
C(#[OH0+])C
respectively
Explanation:
The IR peak at 1687 cm⁻¹ is indicative of an α unsaturated carbonyl carbon. While the 1H NMR singlet is of the methyl group next to carbonyl and the multiplet near 7.1 ppm is a characteristic peak of benzene. This data shows points towards structure I.
Mass spectrum peak at 120 m/z is of molecular ion peak. In the case of carbonyl-containing molecule, this peak is observable. The signal at 105 shows the loss of a methyl group next to the carbonyl. m/z value of 77 is the characteristic cationic peak of benzene, while the peak at 43 infers the formation of acylium ion (RCO+) due to α-cleavage. All this data agrees with the structure of acetophenone (Structure 1)
From the information given, the total volume of rubbing alcohol is 88.2 ml
68.6 % of this volume is isopropanol.
We will assume 88.2 ml represents 100% volume, so the volume of water will be 31.4 %
The volume of isopropanol is
68.6/100 x 88.2 → 0.686 × 88.2 = 60.505 ml
The volume of isopropanol is 60.5 ml.
Volume of water will be 88.20 - 60.5 = 27.7 ml
(27.7 / 88.2 × 100 = 31.4% )
Adding 60.5 ml of isopropanol to 27.7 ml of water to make up 88.2 ml will give 68.6 % v/v isopropanol to water solution.
The answer is a bc it decreases
2.66 molecules of ammonia are produced
Explanation:
We have bellow the chemical reaction between nitrogen (N₂) and hydrogen (H₂) which produce ammonia (NH₃):
N₂ + 3 H₂ → 2 NH₃
From the chemical reaction we see that 1 molecule of nitrogen reacts with 3 molecules of hydrogen, so 4 molecules of nitrogen will react with 12 molecules of hydrogen but we only have 4 molecules of hydrogen available, so the limiting reactant will the hydrogen. Knowing this we devise the following reasoning:
if 3 molecules of hydrogen produces 2 molecules of ammonia
then 4 molecules of hydrogen produces X molecules of ammonia
X = (4 × 2) / 3 = 2.66 molecules of ammonia
However it does not make sense to produce half a molecule of something (you can not do this in the real world), the problem will make sense if you talk about the number of moles of each substance, because in 1 mole of substance you have 6.022 × 10²³ molecules.
You may find in the attached picture the drawing of the molecules.
Learn more about:
limiting reactant
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